If one root of quadratic equation x*2-3x k=0 is 2 then value of k?

Question

Answer

Explanation:

Let's assume another root of the quadratic equation is a. Then, we can write the equation as:

x*2 - 3x k = (x - 2)(x - a)

Expanding the right side of the equation:

x*2 - (a + 2)x + 2a = x*2 - 3x + k

Equating the coefficients of x and the constant terms:

a + 2 = 3

2a = k

Solving the first equation for a:

a = 1

Substituting a = 1 in the second equation:

2a = k

2(1) = k

k = 2

Conclusion:

Therefore, the value of k is 2.

Answer

Let p(x) = x^2 - 3x +k = 0

Put x = 2

(2^2) - 6 + k = 0

4 - 6 + k = 0

-2 + k = 0

k = 2