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60 liters of first mixture of milk and water is mixed with another 40 liters mixture of milk and water. After mixing the mixture, the mixture is sold at the cost of pure milk, then what is the percent profit gained if the ratio of milk to water in the first and second mixture is 7: 5 and 3: 5, respectively? Given below are the steps involved. Arrange them in sequential order.
(A) Amount of milk and water in first mixture is 60 x (7/12) = 35 liters and 60 x (5/12) = 25 liters respectively.
(B) Total amount of milk and water is final mixture is (35 + 15) = 50 liters and (25 + 25) = 50 liters respectively.
(C) Percent profit earned = [(100 - 50)/50] x 100 = 100%
(D) Amount of milk and water in second mixture is 40 x (3/8) = 15 liters and 40 x (5/8) = 25 litres respectively.
(E) Cost price of final mixture = 50 x 1 = 50 and selling price of final mixture = 100 x 1 = 100
  • a)
    BADEC
  • b)
    ADBEC
  • c)
    ADCEB
  • d)
    ADECB
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
60 liters of first mixture of milk and water is mixed with another 40...
The correct arrangement is:
(A) Amount of milk and water in first mixture is 60 x (7/12) = 35 litres and 60 x (5/12) = 25 liters respectively.
(D) Amount of milk and water in second mixture is 40 x (3/8) = 15 liters and 40 x (5/8) = 25 liters respectively.
(B) Total amount of milk and water is final mixture is (35 + 15) = 50 litres and (25 + 25) = 50 liters respectively.
(E) Cost price of final mixture = 50 x 1 = 50 and selling price of final mixture = 100 x 1 = 100
(C) Per cent profit earned = [(100 - 50)/50] x 100 = 100%
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Most Upvoted Answer
60 liters of first mixture of milk and water is mixed with another 40...
Understanding the Mixture Problem
To calculate the percent profit gained from mixing two milk-water mixtures, we need to meticulously follow the steps outlined in the problem. Here’s how to arrange the steps logically:
Step A: First Mixture Calculation
- The first mixture has a total of 60 liters with a milk-to-water ratio of 7:5.
- Amount of milk: 60 x (7/12) = 35 liters
- Amount of water: 60 x (5/12) = 25 liters
Step D: Second Mixture Calculation
- The second mixture has a total of 40 liters with a milk-to-water ratio of 3:5.
- Amount of milk: 40 x (3/8) = 15 liters
- Amount of water: 40 x (5/8) = 25 liters
Step B: Total Mixture Calculation
- After mixing both mixtures:
- Total milk = 35 + 15 = 50 liters
- Total water = 25 + 25 = 50 liters
Step E: Cost Price and Selling Price
- Cost price of the final mixture = 50 liters at cost price of milk = 50 x 1 = 50
- Selling price of the final mixture = Selling as pure milk = 100 x 1 = 100
Step C: Percent Profit Calculation
- Percent profit = [(Selling Price - Cost Price) / Cost Price] x 100
- Percent profit = [(100 - 50) / 50] x 100 = 100%
Conclusion
The correct order of steps to solve the problem is ADBEC, leading to the conclusion that the percent profit earned is 100%. Thus, option 'B' is correct.
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60 liters of first mixture of milk and water is mixed with another 40 liters mixture of milk and water. After mixing the mixture, the mixture is sold at the cost of pure milk, then what is the percent profit gained if the ratio of milk to water in the first and second mixture is 7: 5 and 3: 5, respectively? Given below are the steps involved. Arrange them in sequential order.(A) Amount of milk and water in first mixture is 60 x (7/12) = 35 liters and 60 x (5/12) = 25 liters respectively.(B) Total amount of milk and water is final mixture is (35 + 15) = 50 liters and (25 + 25) = 50 liters respectively.(C) Percent profit earned = [(100 - 50)/50] x 100 = 100%(D) Amount of milk and water in second mixture is 40 x (3/8) = 15 liters and 40 x (5/8) = 25 litres respectively.(E) Cost price of final mixture = 50 x 1 = 50 and selling price of final mixture = 100 x 1 = 100a)BADECb)ADBECc)ADCEBd)ADECBCorrect answer is option 'B'. Can you explain this answer?
Question Description
60 liters of first mixture of milk and water is mixed with another 40 liters mixture of milk and water. After mixing the mixture, the mixture is sold at the cost of pure milk, then what is the percent profit gained if the ratio of milk to water in the first and second mixture is 7: 5 and 3: 5, respectively? Given below are the steps involved. Arrange them in sequential order.(A) Amount of milk and water in first mixture is 60 x (7/12) = 35 liters and 60 x (5/12) = 25 liters respectively.(B) Total amount of milk and water is final mixture is (35 + 15) = 50 liters and (25 + 25) = 50 liters respectively.(C) Percent profit earned = [(100 - 50)/50] x 100 = 100%(D) Amount of milk and water in second mixture is 40 x (3/8) = 15 liters and 40 x (5/8) = 25 litres respectively.(E) Cost price of final mixture = 50 x 1 = 50 and selling price of final mixture = 100 x 1 = 100a)BADECb)ADBECc)ADCEBd)ADECBCorrect answer is option 'B'. Can you explain this answer? for Railways 2024 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about 60 liters of first mixture of milk and water is mixed with another 40 liters mixture of milk and water. After mixing the mixture, the mixture is sold at the cost of pure milk, then what is the percent profit gained if the ratio of milk to water in the first and second mixture is 7: 5 and 3: 5, respectively? Given below are the steps involved. Arrange them in sequential order.(A) Amount of milk and water in first mixture is 60 x (7/12) = 35 liters and 60 x (5/12) = 25 liters respectively.(B) Total amount of milk and water is final mixture is (35 + 15) = 50 liters and (25 + 25) = 50 liters respectively.(C) Percent profit earned = [(100 - 50)/50] x 100 = 100%(D) Amount of milk and water in second mixture is 40 x (3/8) = 15 liters and 40 x (5/8) = 25 litres respectively.(E) Cost price of final mixture = 50 x 1 = 50 and selling price of final mixture = 100 x 1 = 100a)BADECb)ADBECc)ADCEBd)ADECBCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Railways 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 60 liters of first mixture of milk and water is mixed with another 40 liters mixture of milk and water. After mixing the mixture, the mixture is sold at the cost of pure milk, then what is the percent profit gained if the ratio of milk to water in the first and second mixture is 7: 5 and 3: 5, respectively? Given below are the steps involved. Arrange them in sequential order.(A) Amount of milk and water in first mixture is 60 x (7/12) = 35 liters and 60 x (5/12) = 25 liters respectively.(B) Total amount of milk and water is final mixture is (35 + 15) = 50 liters and (25 + 25) = 50 liters respectively.(C) Percent profit earned = [(100 - 50)/50] x 100 = 100%(D) Amount of milk and water in second mixture is 40 x (3/8) = 15 liters and 40 x (5/8) = 25 litres respectively.(E) Cost price of final mixture = 50 x 1 = 50 and selling price of final mixture = 100 x 1 = 100a)BADECb)ADBECc)ADCEBd)ADECBCorrect answer is option 'B'. Can you explain this answer?.
Solutions for 60 liters of first mixture of milk and water is mixed with another 40 liters mixture of milk and water. After mixing the mixture, the mixture is sold at the cost of pure milk, then what is the percent profit gained if the ratio of milk to water in the first and second mixture is 7: 5 and 3: 5, respectively? Given below are the steps involved. Arrange them in sequential order.(A) Amount of milk and water in first mixture is 60 x (7/12) = 35 liters and 60 x (5/12) = 25 liters respectively.(B) Total amount of milk and water is final mixture is (35 + 15) = 50 liters and (25 + 25) = 50 liters respectively.(C) Percent profit earned = [(100 - 50)/50] x 100 = 100%(D) Amount of milk and water in second mixture is 40 x (3/8) = 15 liters and 40 x (5/8) = 25 litres respectively.(E) Cost price of final mixture = 50 x 1 = 50 and selling price of final mixture = 100 x 1 = 100a)BADECb)ADBECc)ADCEBd)ADECBCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Railways. Download more important topics, notes, lectures and mock test series for Railways Exam by signing up for free.
Here you can find the meaning of 60 liters of first mixture of milk and water is mixed with another 40 liters mixture of milk and water. After mixing the mixture, the mixture is sold at the cost of pure milk, then what is the percent profit gained if the ratio of milk to water in the first and second mixture is 7: 5 and 3: 5, respectively? Given below are the steps involved. Arrange them in sequential order.(A) Amount of milk and water in first mixture is 60 x (7/12) = 35 liters and 60 x (5/12) = 25 liters respectively.(B) Total amount of milk and water is final mixture is (35 + 15) = 50 liters and (25 + 25) = 50 liters respectively.(C) Percent profit earned = [(100 - 50)/50] x 100 = 100%(D) Amount of milk and water in second mixture is 40 x (3/8) = 15 liters and 40 x (5/8) = 25 litres respectively.(E) Cost price of final mixture = 50 x 1 = 50 and selling price of final mixture = 100 x 1 = 100a)BADECb)ADBECc)ADCEBd)ADECBCorrect answer is option 'B'. 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Arrange them in sequential order.(A) Amount of milk and water in first mixture is 60 x (7/12) = 35 liters and 60 x (5/12) = 25 liters respectively.(B) Total amount of milk and water is final mixture is (35 + 15) = 50 liters and (25 + 25) = 50 liters respectively.(C) Percent profit earned = [(100 - 50)/50] x 100 = 100%(D) Amount of milk and water in second mixture is 40 x (3/8) = 15 liters and 40 x (5/8) = 25 litres respectively.(E) Cost price of final mixture = 50 x 1 = 50 and selling price of final mixture = 100 x 1 = 100a)BADECb)ADBECc)ADCEBd)ADECBCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for 60 liters of first mixture of milk and water is mixed with another 40 liters mixture of milk and water. After mixing the mixture, the mixture is sold at the cost of pure milk, then what is the percent profit gained if the ratio of milk to water in the first and second mixture is 7: 5 and 3: 5, respectively? Given below are the steps involved. Arrange them in sequential order.(A) Amount of milk and water in first mixture is 60 x (7/12) = 35 liters and 60 x (5/12) = 25 liters respectively.(B) Total amount of milk and water is final mixture is (35 + 15) = 50 liters and (25 + 25) = 50 liters respectively.(C) Percent profit earned = [(100 - 50)/50] x 100 = 100%(D) Amount of milk and water in second mixture is 40 x (3/8) = 15 liters and 40 x (5/8) = 25 litres respectively.(E) Cost price of final mixture = 50 x 1 = 50 and selling price of final mixture = 100 x 1 = 100a)BADECb)ADBECc)ADCEBd)ADECBCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of 60 liters of first mixture of milk and water is mixed with another 40 liters mixture of milk and water. After mixing the mixture, the mixture is sold at the cost of pure milk, then what is the percent profit gained if the ratio of milk to water in the first and second mixture is 7: 5 and 3: 5, respectively? Given below are the steps involved. Arrange them in sequential order.(A) Amount of milk and water in first mixture is 60 x (7/12) = 35 liters and 60 x (5/12) = 25 liters respectively.(B) Total amount of milk and water is final mixture is (35 + 15) = 50 liters and (25 + 25) = 50 liters respectively.(C) Percent profit earned = [(100 - 50)/50] x 100 = 100%(D) Amount of milk and water in second mixture is 40 x (3/8) = 15 liters and 40 x (5/8) = 25 litres respectively.(E) Cost price of final mixture = 50 x 1 = 50 and selling price of final mixture = 100 x 1 = 100a)BADECb)ADBECc)ADCEBd)ADECBCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice 60 liters of first mixture of milk and water is mixed with another 40 liters mixture of milk and water. After mixing the mixture, the mixture is sold at the cost of pure milk, then what is the percent profit gained if the ratio of milk to water in the first and second mixture is 7: 5 and 3: 5, respectively? Given below are the steps involved. Arrange them in sequential order.(A) Amount of milk and water in first mixture is 60 x (7/12) = 35 liters and 60 x (5/12) = 25 liters respectively.(B) Total amount of milk and water is final mixture is (35 + 15) = 50 liters and (25 + 25) = 50 liters respectively.(C) Percent profit earned = [(100 - 50)/50] x 100 = 100%(D) Amount of milk and water in second mixture is 40 x (3/8) = 15 liters and 40 x (5/8) = 25 litres respectively.(E) Cost price of final mixture = 50 x 1 = 50 and selling price of final mixture = 100 x 1 = 100a)BADECb)ADBECc)ADCEBd)ADECBCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Railways tests.
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