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What will be the percentage profit after selling an article at a certain price if there is a loss of 12.5% when the article is sold at half of the previous selling price?
  • a)
    50%
  • b)
    45%
  • c)
    75%
  • d)
    60%
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
What will be the percentage profit after selling an article at a cert...
Suppose the previous selling price = Rs. x
Selling price = Rs. x/2
There is a loss of 12.5% when selling price is Rs. x/2.
Cost Price = x/2 x 100/(100-12.5)= (100 x)/175= 4x/7
Now, when selling price is Rs. x, % profit =[(x-(4x/7))/(4x/7)] x 100 = (3x/4x) x 100 = 75%
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Most Upvoted Answer
What will be the percentage profit after selling an article at a cert...
Calculation of Percentage Profit
1. Let's assume the initial selling price of the article is $100.
2. According to the given information, when the article is sold at half of the previous selling price ($50), there is a loss of 12.5%. This means the selling price is 87.5% of the initial selling price.
3. Therefore, if $50 is 87.5% of the initial selling price, the initial selling price would be $50 / 0.875 = $57.14.
4. Now, the profit can be calculated using the formula: Profit = Selling Price - Cost Price.
5. Profit = $50 - $57.14 = -$7.14.
6. To calculate the percentage profit, we use the formula: Percentage Profit = (Profit / Cost Price) * 100.
7. Percentage Profit = (-$7.14 / $57.14) * 100 ≈ -12.5%.
8. However, since the profit is negative, it indicates a loss, not a profit. Therefore, to find the actual percentage profit, we need to take the absolute value of the profit.
9. Absolute Percentage Profit = 12.5%.
Therefore, the percentage profit after selling the article at a certain price, given the loss of 12.5% when sold at half the previous selling price, is 12.5%.
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What will be the percentage profit after selling an article at a certain price if there is a loss of 12.5% when the article is sold at half of the previous selling price?a)50%b)45%c)75%d)60%Correct answer is option 'C'. Can you explain this answer?
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