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In an election, there were only two candidates. One of the candidates secured 40% of the votes and was defeated by the other candidate by 298 votes. The total number of votes polled is?
  • a)
    1490
  • b)
    2490
  • c)
    1500
  • d)
    1800
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In an election, there were only two candidates. One of the candidates...
Let the total number of votes = 100
20 units = 298
1 unit = 298/20
100 units = 298/20 x 100 = 1490
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Most Upvoted Answer
In an election, there were only two candidates. One of the candidates...
Given:
- There are only two candidates in the election.
- One candidate secured 40% of the votes.
- The other candidate defeated the first candidate by 298 votes.

To find:
- The total number of votes polled.

Approach:
Let's assume the total number of votes polled is 'x'.
- The candidate who secured 40% of the votes received 40% of x votes.
- The other candidate received (100% - 40%) = 60% of x votes.
- The difference in votes between the two candidates is 298.

Calculation:
1. Let's calculate the number of votes secured by the candidate who received 40% of the votes:
- 40% of x = (40/100) * x = 0.4x

2. Let's calculate the number of votes secured by the other candidate:
- 60% of x = (60/100) * x = 0.6x

3. The difference in votes between the two candidates is given as 298:
0.6x - 0.4x = 298
0.2x = 298
x = 298/0.2
x = 1490

Therefore, the total number of votes polled is 1490.

Answer:
The correct answer is option 'A' (1490).
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In an election, there were only two candidates. One of the candidates secured 40% of the votes and was defeated by the other candidate by 298 votes. The total number of votes polled is?a)1490b)2490c)1500d)1800Correct answer is option 'A'. Can you explain this answer?
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