The mean proportion of 9 and 16 is (a) 3 (b) 12 (c) 33 (d) 11?
The mean proportion of 9 and 16 is the middle term of a proportion equation in which 9 and 16 are the two terms. This middle term can be found by using the formula Mean proportion = √(X x y), where x = first value and y = second value. In this case, x = 9 and y = 16. When the calculation is worked out, the mean proportion is found to be 12, which is option (b) in the given question.
First value = 9
Second value = 16
Formula:
Mean proportion = √(X x y)
here x = first value
y = second value
Calculation:
Let mean proportion of 9 and 16 is x
Then 9/x = x/16
x^2 = 16 x 9
x^2 = 144
x = √144
x = 12
This question is part of UPSC exam. View all Class 6 courses
The mean proportion of 9 and 16 is (a) 3 (b) 12 (c) 33 (d) 11?
The mean proportion of 9 and 16 is 12
To find the mean proportion of two numbers, we need to calculate the geometric mean of the two numbers. The geometric mean is the square root of the product of the two numbers.
The formula to find the geometric mean is:
Geometric mean = √(a × b)
Where a and b are the given numbers.
In this case, the two numbers are 9 and 16.
Calculating the geometric mean:
Geometric mean = √(9 × 16)
Geometric mean = √144
Geometric mean = 12
Therefore, the mean proportion of 9 and 16 is 12.
Explanation:
The mean proportion represents the middle value between two numbers, such that the product of the two numbers is equal to the square of the mean proportion. In other words, if a and b are two numbers, the mean proportion is x, then a × b = x^2.
In this case, the numbers are 9 and 16. We need to find the mean proportion between them.
Using the formula for the geometric mean, we calculate the product of the two numbers, which is 9 × 16 = 144. Then, we take the square root of 144, which gives us 12.
Therefore, the mean proportion of 9 and 16 is 12.