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In Trapezium ABCD, AB || DC, ∠A : ∠B = 4:5 and ∠B : ∠C = 3:2 . Find the angles of angles of the trapezium.
Hey Friends Can you do this??? Then pls explain me And send the answer. Pls? Do reply?
Hey Friends Can you do this??? Then pls explain me And send the answer. Pls? Do reply?
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In Trapezium ABCD, AB || DC, ∠A : ∠B = 4:5 and ∠B : ∠C = 3:2 . Find th...
Given:
- Trapezium ABCD
- AB || DC
- ∠A : ∠B = 4:5
- ∠B : ∠C = 3:2
To find:
- The angles of the trapezium
Solution:
Let's assume ∠A = 4x, ∠B = 5x, and ∠C = 3y.
Using the angle sum property of a trapezium:
∠A + ∠B + ∠C + ∠D = 360°
Substituting the given values:
4x + 5x + 3y + ∠D = 360°
9x + 3y + ∠D = 360°
Since AB || DC, ∠D is equal to ∠A.
∠D = 4x
Substituting this value in the equation:
9x + 3y + 4x = 360°
13x + 3y = 360°
Using the given ratio:
∠B : ∠C = 3:2
5x : 3y = 3:2
(5/3)x = (3/2)y
10x = 9y
Now we have two equations:
13x + 3y = 360°
10x = 9y
Solving these equations:
Multiplying the second equation by 13/9 to match the coefficients of x:
(13/9)(10x) = (13/9)(9y)
130x/9 = 13y
130x = 117y
Now we have two equations:
130x = 117y
13x + 3y = 360°
Substituting the value of y from the first equation into the second equation:
13x + 3(130x/117) = 360°
13x + 390x/117 = 360°
(13x * 117 + 390x)/117 = 360°
(13x + 390x)/9 = 360°
403x/9 = 360°
Simplifying the equation:
403x = 9 * 360°
403x = 3240°
x = 3240° / 403
x = 8°
Substituting the value of x in the first equation:
13x + 3y = 360°
13 * 8° + 3y = 360°
104° + 3y = 360°
3y = 360° - 104°
3y = 256°
y = 256° / 3
y = 85⅓°
Calculating the angles:
∠A = 4x = 4 * 8° = 32°
∠B = 5x = 5 * 8° = 40°
∠C = 3y = 3 * 85⅓° ≈ 256°
∠D = ∠A = 32°
Answer:
The angles of the trapezium
- Trapezium ABCD
- AB || DC
- ∠A : ∠B = 4:5
- ∠B : ∠C = 3:2
To find:
- The angles of the trapezium
Solution:
Let's assume ∠A = 4x, ∠B = 5x, and ∠C = 3y.
Using the angle sum property of a trapezium:
∠A + ∠B + ∠C + ∠D = 360°
Substituting the given values:
4x + 5x + 3y + ∠D = 360°
9x + 3y + ∠D = 360°
Since AB || DC, ∠D is equal to ∠A.
∠D = 4x
Substituting this value in the equation:
9x + 3y + 4x = 360°
13x + 3y = 360°
Using the given ratio:
∠B : ∠C = 3:2
5x : 3y = 3:2
(5/3)x = (3/2)y
10x = 9y
Now we have two equations:
13x + 3y = 360°
10x = 9y
Solving these equations:
Multiplying the second equation by 13/9 to match the coefficients of x:
(13/9)(10x) = (13/9)(9y)
130x/9 = 13y
130x = 117y
Now we have two equations:
130x = 117y
13x + 3y = 360°
Substituting the value of y from the first equation into the second equation:
13x + 3(130x/117) = 360°
13x + 390x/117 = 360°
(13x * 117 + 390x)/117 = 360°
(13x + 390x)/9 = 360°
403x/9 = 360°
Simplifying the equation:
403x = 9 * 360°
403x = 3240°
x = 3240° / 403
x = 8°
Substituting the value of x in the first equation:
13x + 3y = 360°
13 * 8° + 3y = 360°
104° + 3y = 360°
3y = 360° - 104°
3y = 256°
y = 256° / 3
y = 85⅓°
Calculating the angles:
∠A = 4x = 4 * 8° = 32°
∠B = 5x = 5 * 8° = 40°
∠C = 3y = 3 * 85⅓° ≈ 256°
∠D = ∠A = 32°
Answer:
The angles of the trapezium
Community Answer
In Trapezium ABCD, AB || DC, ∠A : ∠B = 4:5 and ∠B : ∠C = 3:2 . Find th...
Pls recheck the given question...i think its wrong
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In Trapezium ABCD, AB || DC, ∠A : ∠B = 4:5 and ∠B : ∠C = 3:2 . Find the angles of angles of the trapezium.Hey Friends Can you do this??? Then pls explain me And send the answer. Pls? Do reply?
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In Trapezium ABCD, AB || DC, ∠A : ∠B = 4:5 and ∠B : ∠C = 3:2 . Find the angles of angles of the trapezium.Hey Friends Can you do this??? Then pls explain me And send the answer. Pls? Do reply? for Class 8 2024 is part of Class 8 preparation. The Question and answers have been prepared according to the Class 8 exam syllabus. Information about In Trapezium ABCD, AB || DC, ∠A : ∠B = 4:5 and ∠B : ∠C = 3:2 . Find the angles of angles of the trapezium.Hey Friends Can you do this??? Then pls explain me And send the answer. Pls? Do reply? covers all topics & solutions for Class 8 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Trapezium ABCD, AB || DC, ∠A : ∠B = 4:5 and ∠B : ∠C = 3:2 . Find the angles of angles of the trapezium.Hey Friends Can you do this??? Then pls explain me And send the answer. Pls? Do reply?.
In Trapezium ABCD, AB || DC, ∠A : ∠B = 4:5 and ∠B : ∠C = 3:2 . Find the angles of angles of the trapezium.Hey Friends Can you do this??? Then pls explain me And send the answer. Pls? Do reply? for Class 8 2024 is part of Class 8 preparation. The Question and answers have been prepared according to the Class 8 exam syllabus. Information about In Trapezium ABCD, AB || DC, ∠A : ∠B = 4:5 and ∠B : ∠C = 3:2 . Find the angles of angles of the trapezium.Hey Friends Can you do this??? Then pls explain me And send the answer. Pls? Do reply? covers all topics & solutions for Class 8 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Trapezium ABCD, AB || DC, ∠A : ∠B = 4:5 and ∠B : ∠C = 3:2 . Find the angles of angles of the trapezium.Hey Friends Can you do this??? Then pls explain me And send the answer. Pls? Do reply?.
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