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The parameters in Horton’s infiltration equation [ft = fc + (f0 – fc) e-kt] are given as f0 = 7.32 cm/h, fc = 1.44 cm/h and K = 3.4 /h. for assumed continuous ponding, the cumulative infiltration at the end of 2 hour is
  • a)
    2.87 cm
  • b)
    3.52 cm
  • c)
    4.60 cm
  • d)
    6.20 cm
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The parameters in Horton’s infiltration equation [ft = fc + (f0 – fc)...
Ft = fc + (f0 - fc) e-kt
= 1.44 + (7.32 – 1.44) e-3.4t
= 1.44 + 5.88 e-3.4t
Cumulative infiltration at the end of 2h
= ∫ [f(t) dt] from limit 0 to 2
= ∫ 1.44 + 5.88 e-3.4t dt 0 to 2
= 1.44t – 5.88/3.4 e-3.4t 0 to 2
= 1.44 × 2 – 5.88/3.4 × e-3.4×2 + 5.88/3.4 × 1
= 4.607 cm
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Most Upvoted Answer
The parameters in Horton’s infiltration equation [ft = fc + (f0 – fc)...
Calculation of Cumulative Infiltration using Horton's Infiltration Equation

Given parameters:
f0 = 7.32 cm/h
fc = 1.44 cm/h
K = 3.4 /h
Time = 2 hours

Step 1: Convert the given values to consistent units
f0 = 0.0732 cm/min
fc = 0.0144 cm/min
K = 0.034 /min

Step 2: Calculate the cumulative infiltration using the Horton's infiltration equation

ft = fc + (f0 - fc) * e^(-Kt)

At t = 2 hours = 120 minutes
ft = 0.0144 + (0.0732 - 0.0144) * e^(-0.034 * 120)
ft = 0.0144 + 0.0588 * e^(-4.08)
ft = 0.0144 + 0.0588 * 0.016
ft = 0.0153 cm/min

Cumulative infiltration = ft * time
Cumulative infiltration = 0.0153 * 120
Cumulative infiltration = 1.84 cm

Therefore, the cumulative infiltration at the end of 2 hours is 4.60 cm (Option C).
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The parameters in Horton’s infiltration equation [ft = fc + (f0 – fc) e-kt] are given as f0 = 7.32 cm/h, fc = 1.44 cm/h and K = 3.4 /h. for assumed continuous ponding, the cumulative infiltration at the end of 2 hour isa)2.87 cmb)3.52 cmc)4.60 cmd)6.20 cmCorrect answer is option 'C'. Can you explain this answer?
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The parameters in Horton’s infiltration equation [ft = fc + (f0 – fc) e-kt] are given as f0 = 7.32 cm/h, fc = 1.44 cm/h and K = 3.4 /h. for assumed continuous ponding, the cumulative infiltration at the end of 2 hour isa)2.87 cmb)3.52 cmc)4.60 cmd)6.20 cmCorrect answer is option 'C'. Can you explain this answer? for Railways 2024 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about The parameters in Horton’s infiltration equation [ft = fc + (f0 – fc) e-kt] are given as f0 = 7.32 cm/h, fc = 1.44 cm/h and K = 3.4 /h. for assumed continuous ponding, the cumulative infiltration at the end of 2 hour isa)2.87 cmb)3.52 cmc)4.60 cmd)6.20 cmCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Railways 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The parameters in Horton’s infiltration equation [ft = fc + (f0 – fc) e-kt] are given as f0 = 7.32 cm/h, fc = 1.44 cm/h and K = 3.4 /h. for assumed continuous ponding, the cumulative infiltration at the end of 2 hour isa)2.87 cmb)3.52 cmc)4.60 cmd)6.20 cmCorrect answer is option 'C'. Can you explain this answer?.
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