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A circular disc of diameter ‘d’ is slowly rotated in a liquid of large viscosity μ at a small distance h from a fixed surface. The minimum torque required to maintain an angular velocity ω will be
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A circular disc of diameter ‘d’ is slowly rotated in a liquid of larg...
Consider an element of disc at a distance r and having width dr.
Linear velocity at the radius = rw
Shear stress =
Torque = shear stress x area x r
Assuming that gap h is small so that velocity distribution may be assumed linear
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Most Upvoted Answer
A circular disc of diameter ‘d’ is slowly rotated in a liquid of larg...
Consider an element of disc at a distance r and having width dr.
Linear velocity at the radius = rw
Shear stress =
Torque = shear stress x area x r
Assuming that gap h is small so that velocity distribution may be assumed linear
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Community Answer
A circular disc of diameter ‘d’ is slowly rotated in a liquid of larg...
Consider an element of disc at a distance r and having width dr.
Linear velocity at the radius = rw
Shear stress =
Torque = shear stress x area x r
Assuming that gap h is small so that velocity distribution may be assumed linear
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A circular disc of diameter ‘d’ is slowly rotated in a liquid of large viscosity μ at a small distance h from a fixed surface. The minimum torque required to maintain an angular velocity ω will bea)b)c)d)Correct answer is option 'A'. Can you explain this answer?
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