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If 2^(2x 3)-3^2.2^x 1=0 then the values of x are?
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If 2^(2x 3)-3^2.2^x 1=0 then the values of x are?
Solution:

Given equation is: 2^(2x 3)-3^2.2^x 1=0

We need to solve for x.

We can simplify the given equation as follows:

2^(2x) * 3^(-2) - 2^x = 0

Step 1: Convert the equation into a quadratic form.

Let y = 2^x, then the equation becomes:

y^2 * 3^(-2) - y = 0

Multiplying both sides by 3^2, we get:

3^2 * y^2 * 3^(-2) - 3^2 * y = 0

Simplifying, we get:

3y^2 - 9y = 0

Dividing both sides by 3y, we get:

y - 3 = 0 or y = 0

Step 2: Solve for x.

Substituting y = 2^x, we get:

2^x - 3 = 0 or 2^x = 3

Taking logarithm (base 2) of both sides, we get:

x = log2(3)

Therefore, the values of x are x = log2(3).

Final Answer: x = log2(3).
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If 2^(2x 3)-3^2.2^x 1=0 then the values of x are?
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If 2^(2x 3)-3^2.2^x 1=0 then the values of x are? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about If 2^(2x 3)-3^2.2^x 1=0 then the values of x are? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If 2^(2x 3)-3^2.2^x 1=0 then the values of x are?.
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