The cost of petrol X is Rs.6 per litre while petrol Y is only half as ...
To find the cost of filling 1/3 of the tank with petrol X and the rest with petrol Y, we first need to calculate the volume of the tank.
Given that each side of the cubical tank is 20 cm long, the volume of the tank can be calculated as:
Volume = (side length)^3 = (20 cm)^3 = 8000 cm^3
Now, we need to find the cost of filling 1/3 of the tank with petrol X. Since petrol X costs Rs. 6 per litre, we need to find the volume of 1/3 of the tank in litres and then multiply it by the cost of petrol X.
Volume of 1/3 of the tank = (1/3) * 8000 cm^3 = 2666.67 cm^3
1 litre = 1000 cm^3, so the volume of 1/3 of the tank in litres is:
Volume in litres = 2666.67 cm^3 / 1000 cm^3/litre = 2.67 litres
Cost of filling 1/3 of the tank with petrol X = Volume in litres * Cost per litre = 2.67 litres * Rs. 6/litre = Rs. 16.02
Since we cannot have a fraction of a paisa in the cost, we round it up to the nearest paisa, which gives us Rs. 16.
Now, we need to find the cost of filling the remaining 2/3 of the tank with petrol Y. Petrol Y is only half as expensive as petrol X, so its cost per litre is Rs. 6/2 = Rs. 3.
Volume of 2/3 of the tank = (2/3) * 8000 cm^3 = 5333.33 cm^3
Volume in litres = 5333.33 cm^3 / 1000 cm^3/litre = 5.33 litres
Cost of filling 2/3 of the tank with petrol Y = Volume in litres * Cost per litre = 5.33 litres * Rs. 3/litre = Rs. 15.99
Rounding it up to the nearest paisa gives us Rs. 16.
Hence, the total cost of filling 1/3 of the tank with petrol X and the rest with petrol Y is Rs. 16 + Rs. 16 = Rs. 32.
Therefore, the correct answer is option (b) Rs. 32.