Introduction:
In this question, we are given a set of integers and we need to determine which integer will always remain in the middle when the set is arranged in ascending or descending order. The given integers are 10, 0, 5, -5, and -7.

Ascending Order:
To arrange the integers in ascending order, we start with the smallest integer and place it first. Then we proceed to place the next smallest integer and continue this process until all the integers are arranged in ascending order.

Descending Order:
To arrange the integers in descending order, we start with the largest integer and place it first. Then we proceed to place the next largest integer and continue this process until all the integers are arranged in descending order.

Analysis:
Let's arrange the given integers in both ascending and descending order to determine which integer remains in the middle.

Ascending Order:
-7, -5, 0, 5, 10

Descending Order:
10, 5, 0, -5, -7

Conclusion:
From the arrangement in both ascending and descending order, we can observe that the integer 0 always remains in the middle. Therefore, the correct answer is option (a) 0.

Explanation:
When the given integers are arranged in ascending order, the integer 0 is placed in the middle because it is neither the largest nor the smallest integer in the set. Similarly, when the integers are arranged in descending order, the integer 0 is again placed in the middle. This is because it is equidistant from the largest and smallest integer in the set.

Hence, the integer 0 always remains in the middle of the arrangement, regardless of whether it is in ascending or descending order.

"OPTION (A) 0" CAN ANYONE EXPLAIN?