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The magnifying power of a telescope is nine. When it is adjusted for parallel rays, the distance between the objective and eyepiece is 20 cm. The focal length of the objective and eyepiece are respectively
  • a)
    10 cm, 10 cm
  • b)
    18 cm, 2 cm
  • c)
    15 cm, 5 cm
  • d)
    11 cm, 9cm
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The magnifying power of a telescope is nine. When it is adjusted for ...
For the final image at infinity, magnifying power of a telescope is given by
where, m = magnification,
fο = focal length of objective
and fe = focal length of eyepiece
⇒ fο = 9fe …(i)
Also, distance between objective and eyepiece
⇒ fο = fe = (given)
⇒ 9fe + fe = 20 ⇒ fe = 2 cm
⇒ fο = 9fe = 18 cm
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The magnifying power of a telescope is nine. When it is adjusted for parallel rays, the distance between the objective and eyepiece is 20 cm. The focal length of the objective and eyepiece are respectivelya)10 cm, 10 cmb)18 cm, 2 cmc)15 cm, 5 cmd)11 cm, 9cmCorrect answer is option 'B'. Can you explain this answer?
Question Description
The magnifying power of a telescope is nine. When it is adjusted for parallel rays, the distance between the objective and eyepiece is 20 cm. The focal length of the objective and eyepiece are respectivelya)10 cm, 10 cmb)18 cm, 2 cmc)15 cm, 5 cmd)11 cm, 9cmCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The magnifying power of a telescope is nine. When it is adjusted for parallel rays, the distance between the objective and eyepiece is 20 cm. The focal length of the objective and eyepiece are respectivelya)10 cm, 10 cmb)18 cm, 2 cmc)15 cm, 5 cmd)11 cm, 9cmCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The magnifying power of a telescope is nine. When it is adjusted for parallel rays, the distance between the objective and eyepiece is 20 cm. The focal length of the objective and eyepiece are respectivelya)10 cm, 10 cmb)18 cm, 2 cmc)15 cm, 5 cmd)11 cm, 9cmCorrect answer is option 'B'. Can you explain this answer?.
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