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If 3x + 2y + z = 0, x + 4y+z = 0, 2x+ y + 4z = 0 be a system of equations, then
  • a)
    it is inconsistent
  • b)
    it has only trivial solution
  • c)
    it can be reduced to a single equation and so a solution does not exist
  • d)
    the determinant of the matrix of coefficient is zero
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If 3x + 2y + z = 0, x + 4y+z = 0, 2x+ y+ 4z = 0 be a system of equatio...
Given:
The system of equations is:
1) 3x + 2y + z = 0
2) x + 4y + z = 0
3) 2x + y + 4z = 0

To find:
The nature of the system of equations.

Solution:
To determine the nature of the system of equations, we need to consider the coefficient matrix and solve it using the determinant method.

Determinant Method:
The system of equations can be written in matrix form as AX = 0, where A is the coefficient matrix and X is the column matrix of variables (x, y, z).

The coefficient matrix A is given by:
A = |3 2 1|
|1 4 1|
|2 1 4|

The determinant of the coefficient matrix is calculated as follows:
|A| = 3(4*4 - 1*1) - 2(1*4 - 2*1) + 1(1*1 - 2*4)
= 3(16 - 1) - 2(4 - 2) + 1(1 - 8)
= 3(15) - 2(2) + 1(-7)
= 45 - 4 - 7
= 34

Analysis:
If the determinant of the coefficient matrix (|A|) is zero, then the system of equations has either no solution or infinitely many solutions. If |A| is non-zero, then the system has a unique solution.

Conclusion:
Since the determinant of the coefficient matrix is non-zero (34 ≠ 0), the system of equations has a unique solution. Therefore, the correct answer is option 'B' - the system of equations has only a trivial solution.
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If 3x + 2y + z = 0, x + 4y+z = 0, 2x+ y+ 4z = 0 be a system of equations, thena)it is inconsistentb)it has only trivial solutionc)it can be reduced to a single equation and so a solution does not existd)the determinant of the matrix of coefficient is zeroCorrect answer is option 'B'. Can you explain this answer?
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