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Concentrations of three solutions A, B and C are 20%, 30% and 40% respectively. They are mixed in the ratio 3: 5: x resulting in a solution of 30% concentration. Find x
  • a)
    5
  • b)
    2
  • c)
    3
  • d)
    4
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Concentrations of three solutions A, B and C are 20%, 30% and 40% res...
3 × 0.2 + 5 × 0.3 + x × 0.4 = 0.3 (3+5+x)
⇒ 2.1 + 0.4x = 0.3(8+x)
⇒ 2.1 + 0.4x = 2.4 + 0.3x
or, x = 3
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Concentrations of three solutions A, B and C are 20%, 30% and 40% res...
Given: Concentrations of solutions A, B and C are 20%, 30% and 40% respectively. They are mixed in the ratio 3: 5: x resulting in a solution of 30% concentration. We need to find the value of x.

Approach:

Let's assume the total quantity of the mixture to be 100 units. Then, the quantity of solution A, B and C would be:

- Quantity of solution A = (3/8) * 100 = 37.5 units
- Quantity of solution B = (5/8) * 100 = 62.5 units
- Quantity of solution C = x * 100

Now, we can write the equation for the concentration of the mixture as follows:

(20/100) * 37.5 + (30/100) * 62.5 + (40/100) * (x * 100) = (30/100) * 100

Simplifying the above equation, we get:

7.5 + 18.75 + 40x/100 = 30

40x/100 = 3.75

x = 3.75 * 100 / 40 = 9.375

Therefore, the value of x is 9.375.

Answer: Option (c) 3.
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Concentrations of three solutions A, B and C are 20%, 30% and 40% respectively. They are mixed in the ratio 3: 5: x resulting in a solution of 30% concentration. Find xa)5b)2c)3d)4Correct answer is option 'C'. Can you explain this answer?
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