Directions: In the following questions, A statement of Assertion (A) ...
In the complexes, Co exists as Co2+ and Fe as Fe2+. Both of the complexes become Stable by oxidation of metal ion to Co3+ and Fe3+.
Directions: In the following questions, A statement of Assertion (A) ...
Assertion (A): [Cr(H2O)6]Cl2 and [Fe(H2O)6]Cl2 are reducing in nature.
Reason (R): Unpaired electrons are present in their d-orbitals.
The correct answer is option 'B' - Both A and R are true but R is NOT the correct explanation of A.
- The Assertion states that [Cr(H2O)6]Cl2 and [Fe(H2O)6]Cl2 are reducing in nature.
- The Reason states that unpaired electrons are present in their d-orbitals.
Explanation:
- The complex ions [Cr(H2O)6]2+ and [Fe(H2O)6]2+ both have unpaired electrons in their d-orbitals.
- The presence of unpaired electrons in the d-orbitals of these complex ions makes them paramagnetic, which means they are attracted to a magnetic field.
- This paramagnetic property is a characteristic of reducing agents, as they are capable of donating electrons to other species.
- In the case of [Cr(H2O)6]2+ and [Fe(H2O)6]2+, the metal ions (Cr2+ and Fe2+) can donate their unpaired electrons to other species, thereby acting as reducing agents.
- The reducing nature of these complex ions is not solely dependent on the presence of unpaired electrons in their d-orbitals.
- Other factors such as the nature of the ligands, stability of the complex, and the redox potential of the metal ion also play a role in determining the reducing nature of a complex ion.
- Therefore, while the Reason is true and correctly explains the presence of unpaired electrons in the d-orbitals of these complex ions, it does not fully explain why they are reducing in nature.
- Hence, the correct answer is option 'B' - Both A and R are true but R is NOT the correct explanation of A.