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According to wave theory of light, the light of any frequency can emit electrons from metallic surface provided the intensity of light be sufficient to provide necessary energy for emission of electrons, but according to experimental observations, the light of frequency less than threshold frequency can not emit electrons; whatever be the intensity of incident light. Einstein also proposed that electromagnetic radiation is quantised.
If photoelectrons are ejected from a surface when light of wavelength λ1 = 550 nm is incident on it. The stopping potential for such electrons is Vs =0.19 . Suppose the radiation of wavelength λ2 = 190 nm is incident on the surface.
Q. Calculate the threshold frequency for the surface.
  • a)
    500 x 1012 Hz
  • b)
    480 x 1013 Hz
  • c)
    520 x 1011 Hz
  • d)
    460 x 1013 Hz
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
According to wave theory of light, the light of any frequency can emi...
Using Einstein's equation for photoelectric effect,
In the first case, eVs1 ​= hc/λ1 ​− W ....(1) where W= work function of metal surface.
Since the work function does not depend on the wavelength of incident light, it will be constant for both cases.
Thus, W = hc/λ1 - eVs1
or W = - (1.6 × 10−19)(0.19) = 3.31 × 10−19J
If ν0 ​be the threshold frequency for the metal surface, then W = hν0
or ν0 = = 0.5 × 1015 = 500 × 1012Hz
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According to wave theory of light, the light of any frequency can emi...
Question Analysis:
In this question, we are given the wavelength of incident light, λ1, and the stopping potential, Vs, for the photoelectrons emitted from a metallic surface. We are also given the wavelength of another incident light, λ2. We are asked to calculate the threshold frequency for the surface.

Concepts Involved:
1. Photoelectric Effect: According to the wave theory of light, the intensity of light should determine the energy of ejected electrons. However, experimental observations show that the frequency of light determines whether or not electrons will be emitted. If the frequency of the incident light is less than the threshold frequency, no electrons are emitted irrespective of the intensity of light. If the frequency is equal to or greater than the threshold frequency, electrons are emitted.

2. Stopping Potential: When electrons are emitted from a metallic surface due to the photoelectric effect, they form a current. The stopping potential is the minimum potential difference required to stop the photoelectric current.

Solution:
To calculate the threshold frequency, we need to find the frequency of the incident light for which the stopping potential is zero. We can use the formula:

Vs = (h / e) * (f - f0)

Where:
- Vs is the stopping potential,
- h is Planck's constant (6.626 x 10^-34 J s),
- e is the charge of an electron (1.6 x 10^-19 C),
- f is the frequency of the incident light, and
- f0 is the threshold frequency.

Since Vs = 0.19 and we are given λ1 = 550 nm, we can calculate the frequency f1 using the equation:

c = λ1 * f1

Where:
- c is the speed of light (3 x 10^8 m/s).

Using these values, we can calculate f1 as:

f1 = c / λ1

Next, we can substitute the values of Vs, h, e, and f1 into the formula to find f0:

0.19 = (6.626 x 10^-34 J s / 1.6 x 10^-19 C) * (f1 - f0)

Simplifying the equation:

f1 - f0 = 0.19 * (1.6 x 10^-19 C / 6.626 x 10^-34 J s)

f0 = f1 - (0.19 * (1.6 x 10^-19 C / 6.626 x 10^-34 J s))

Finally, we substitute the values of f1 and solve for f0:

f0 = f1 - (0.19 * (1.6 x 10^-19 C / 6.626 x 10^-34 J s))

f0 ≈ 5.0 x 10^14 Hz

Therefore, the threshold frequency for the surface is approximately 5.0 x 10^14 Hz, which corresponds to option A.
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According to wave theory of light, the light of any frequency can emit electrons from metallic surface provided the intensity of light be sufficient to provide necessary energy for emission of electrons, but according to experimental observations, the light of frequency less than threshold frequency can not emit electrons; whatever be the intensity of incident light. Einstein also proposed that electromagnetic radiation is quantised.If photoelectrons are ejected from a surface when light of wavelength λ1 = 550 nm is incident on it. The stopping potential for such electrons is Vs =0.19 . Suppose the radiation of wavelength λ2 = 190 nm is incident on the surface.Q. Calculate the threshold frequency for the surface.a)500 x 1012 Hzb)480 x 1013 Hzc)520 x 1011 Hzd)460 x 1013 HzCorrect answer is option 'A'. Can you explain this answer?
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According to wave theory of light, the light of any frequency can emit electrons from metallic surface provided the intensity of light be sufficient to provide necessary energy for emission of electrons, but according to experimental observations, the light of frequency less than threshold frequency can not emit electrons; whatever be the intensity of incident light. Einstein also proposed that electromagnetic radiation is quantised.If photoelectrons are ejected from a surface when light of wavelength λ1 = 550 nm is incident on it. The stopping potential for such electrons is Vs =0.19 . Suppose the radiation of wavelength λ2 = 190 nm is incident on the surface.Q. Calculate the threshold frequency for the surface.a)500 x 1012 Hzb)480 x 1013 Hzc)520 x 1011 Hzd)460 x 1013 HzCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about According to wave theory of light, the light of any frequency can emit electrons from metallic surface provided the intensity of light be sufficient to provide necessary energy for emission of electrons, but according to experimental observations, the light of frequency less than threshold frequency can not emit electrons; whatever be the intensity of incident light. Einstein also proposed that electromagnetic radiation is quantised.If photoelectrons are ejected from a surface when light of wavelength λ1 = 550 nm is incident on it. The stopping potential for such electrons is Vs =0.19 . Suppose the radiation of wavelength λ2 = 190 nm is incident on the surface.Q. Calculate the threshold frequency for the surface.a)500 x 1012 Hzb)480 x 1013 Hzc)520 x 1011 Hzd)460 x 1013 HzCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for According to wave theory of light, the light of any frequency can emit electrons from metallic surface provided the intensity of light be sufficient to provide necessary energy for emission of electrons, but according to experimental observations, the light of frequency less than threshold frequency can not emit electrons; whatever be the intensity of incident light. Einstein also proposed that electromagnetic radiation is quantised.If photoelectrons are ejected from a surface when light of wavelength λ1 = 550 nm is incident on it. The stopping potential for such electrons is Vs =0.19 . Suppose the radiation of wavelength λ2 = 190 nm is incident on the surface.Q. Calculate the threshold frequency for the surface.a)500 x 1012 Hzb)480 x 1013 Hzc)520 x 1011 Hzd)460 x 1013 HzCorrect answer is option 'A'. Can you explain this answer?.
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