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According to wave theory of light, the light of any frequency can emit electrons from metallic surface provided the intensity of light be sufficient to provide necessary energy for emission of electrons, but according to experimental observations, the light of frequency less than threshold frequency can not emit electrons; whatever be the intensity of incident light. Einstein also proposed that electromagnetic radiation is quantised.
If photoelectrons are ejected from a surface when light of wavelength λ1 = 550 nm is incident on it. The stopping potential for such electrons is Vs =0.19 . Suppose the radiation of wavelength λ2 = 190 nm is incident on the surface.
Q. Calculate the stopping potential Vs2 of the surface.
- a)4.47
- b)3.16
- c)2.76
- d)5.28
Correct answer is option 'A'. Can you explain this answer?
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According to wave theory of light, the light of any frequency can emi...
Using the Einstein's equation for photoelectric effect
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In the first case, eVs1 = hc/λ1 − W ....(1) where W = work function of metal surface.
And in second case, eVs2 = hc/λ2 − W ....(2)
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According to wave theory of light, the light of any frequency can emi...
Explanation:
According to the wave theory of light, the intensity of light determines the amplitude of the wave, which in turn determines the energy carried by the wave. Therefore, according to this theory, the intensity of light should be sufficient to provide the necessary energy for the emission of electrons from a metallic surface.
However, experimental observations showed that even if the intensity of light is increased, the light of frequency lower than the threshold frequency cannot emit electrons. This observation could not be explained by the wave theory of light.
Albert Einstein proposed the concept of quantization of electromagnetic radiation to explain the photoelectric effect. According to this theory, light is made up of discrete packets of energy called photons. The energy of each photon is given by the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency of the light.
When a photon with sufficient energy (equal to or greater than the work function of the material) is incident on a metallic surface, it can transfer its energy to an electron and eject it from the surface. The remaining energy of the photon is converted into the kinetic energy of the ejected electron.
Now let's calculate the stopping potential Vs2 for the given scenario.
We are given the wavelength of the incident light λ2 = 190 nm. To calculate the frequency of the light, we can use the equation c = λf, where c is the speed of light.
c = 3 × 10^8 m/s (speed of light)
λ2 = 190 nm = 190 × 10^-9 m (wavelength)
By rearranging the equation, we can solve for f:
f = c/λ2
f = (3 × 10^8 m/s) / (190 × 10^-9 m)
f ≈ 1.58 × 10^15 Hz
Now, we can calculate the energy of the incident photon using the equation E = hf:
E = (6.63 × 10^-34 J·s) × (1.58 × 10^15 Hz)
E ≈ 1.05 × 10^-18 J
Since the stopping potential Vs2 is the potential required to stop the ejected electron, it is equal to the kinetic energy of the electron.
Using the equation for kinetic energy:
E = 1/2 mv^2
where m is the mass of the electron and v is its velocity.
We can rearrange the equation to solve for v:
v = √(2E/m)
Substituting the values, we get:
v = √(2 × 1.05 × 10^-18 J / (9.11 × 10^-31 kg))
v ≈ 5.53 × 10^6 m/s
The stopping potential Vs2 is equal to the kinetic energy of the electron divided by its charge:
Vs2 = E/q
where q is the charge of the electron.
Vs2 = (1.05 × 10^-18 J) / (1.6 × 10^-19 C)
Vs2 ≈ 6.56 V
So the stopping potential Vs2 of the surface is approximately 6.56 V, which is closest to option A (4.47 V).
According to the wave theory of light, the intensity of light determines the amplitude of the wave, which in turn determines the energy carried by the wave. Therefore, according to this theory, the intensity of light should be sufficient to provide the necessary energy for the emission of electrons from a metallic surface.
However, experimental observations showed that even if the intensity of light is increased, the light of frequency lower than the threshold frequency cannot emit electrons. This observation could not be explained by the wave theory of light.
Albert Einstein proposed the concept of quantization of electromagnetic radiation to explain the photoelectric effect. According to this theory, light is made up of discrete packets of energy called photons. The energy of each photon is given by the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency of the light.
When a photon with sufficient energy (equal to or greater than the work function of the material) is incident on a metallic surface, it can transfer its energy to an electron and eject it from the surface. The remaining energy of the photon is converted into the kinetic energy of the ejected electron.
Now let's calculate the stopping potential Vs2 for the given scenario.
We are given the wavelength of the incident light λ2 = 190 nm. To calculate the frequency of the light, we can use the equation c = λf, where c is the speed of light.
c = 3 × 10^8 m/s (speed of light)
λ2 = 190 nm = 190 × 10^-9 m (wavelength)
By rearranging the equation, we can solve for f:
f = c/λ2
f = (3 × 10^8 m/s) / (190 × 10^-9 m)
f ≈ 1.58 × 10^15 Hz
Now, we can calculate the energy of the incident photon using the equation E = hf:
E = (6.63 × 10^-34 J·s) × (1.58 × 10^15 Hz)
E ≈ 1.05 × 10^-18 J
Since the stopping potential Vs2 is the potential required to stop the ejected electron, it is equal to the kinetic energy of the electron.
Using the equation for kinetic energy:
E = 1/2 mv^2
where m is the mass of the electron and v is its velocity.
We can rearrange the equation to solve for v:
v = √(2E/m)
Substituting the values, we get:
v = √(2 × 1.05 × 10^-18 J / (9.11 × 10^-31 kg))
v ≈ 5.53 × 10^6 m/s
The stopping potential Vs2 is equal to the kinetic energy of the electron divided by its charge:
Vs2 = E/q
where q is the charge of the electron.
Vs2 = (1.05 × 10^-18 J) / (1.6 × 10^-19 C)
Vs2 ≈ 6.56 V
So the stopping potential Vs2 of the surface is approximately 6.56 V, which is closest to option A (4.47 V).
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According to wave theory of light, the light of any frequency can emit electrons from metallic surface provided the intensity of light be sufficient to provide necessary energy for emission of electrons, but according to experimental observations, the light of frequency less than threshold frequency can not emit electrons; whatever be the intensity of incident light. Einstein also proposed that electromagnetic radiation is quantised.If photoelectrons are ejected from a surface when light of wavelength λ1 = 550 nm is incident on it. The stopping potential for such electrons is Vs =0.19 . Suppose the radiation of wavelength λ2 = 190 nm is incident on the surface.Q. Calculate the stopping potential Vs2 of the surface.a)4.47b)3.16c)2.76d)5.28Correct answer is option 'A'. Can you explain this answer?
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According to wave theory of light, the light of any frequency can emit electrons from metallic surface provided the intensity of light be sufficient to provide necessary energy for emission of electrons, but according to experimental observations, the light of frequency less than threshold frequency can not emit electrons; whatever be the intensity of incident light. Einstein also proposed that electromagnetic radiation is quantised.If photoelectrons are ejected from a surface when light of wavelength λ1 = 550 nm is incident on it. The stopping potential for such electrons is Vs =0.19 . Suppose the radiation of wavelength λ2 = 190 nm is incident on the surface.Q. Calculate the stopping potential Vs2 of the surface.a)4.47b)3.16c)2.76d)5.28Correct answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about According to wave theory of light, the light of any frequency can emit electrons from metallic surface provided the intensity of light be sufficient to provide necessary energy for emission of electrons, but according to experimental observations, the light of frequency less than threshold frequency can not emit electrons; whatever be the intensity of incident light. Einstein also proposed that electromagnetic radiation is quantised.If photoelectrons are ejected from a surface when light of wavelength λ1 = 550 nm is incident on it. The stopping potential for such electrons is Vs =0.19 . Suppose the radiation of wavelength λ2 = 190 nm is incident on the surface.Q. Calculate the stopping potential Vs2 of the surface.a)4.47b)3.16c)2.76d)5.28Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for According to wave theory of light, the light of any frequency can emit electrons from metallic surface provided the intensity of light be sufficient to provide necessary energy for emission of electrons, but according to experimental observations, the light of frequency less than threshold frequency can not emit electrons; whatever be the intensity of incident light. Einstein also proposed that electromagnetic radiation is quantised.If photoelectrons are ejected from a surface when light of wavelength λ1 = 550 nm is incident on it. The stopping potential for such electrons is Vs =0.19 . Suppose the radiation of wavelength λ2 = 190 nm is incident on the surface.Q. Calculate the stopping potential Vs2 of the surface.a)4.47b)3.16c)2.76d)5.28Correct answer is option 'A'. Can you explain this answer?.
Solutions for According to wave theory of light, the light of any frequency can emit electrons from metallic surface provided the intensity of light be sufficient to provide necessary energy for emission of electrons, but according to experimental observations, the light of frequency less than threshold frequency can not emit electrons; whatever be the intensity of incident light. Einstein also proposed that electromagnetic radiation is quantised.If photoelectrons are ejected from a surface when light of wavelength λ1 = 550 nm is incident on it. The stopping potential for such electrons is Vs =0.19 . Suppose the radiation of wavelength λ2 = 190 nm is incident on the surface.Q. Calculate the stopping potential Vs2 of the surface.a)4.47b)3.16c)2.76d)5.28Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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ample number of questions to practice According to wave theory of light, the light of any frequency can emit electrons from metallic surface provided the intensity of light be sufficient to provide necessary energy for emission of electrons, but according to experimental observations, the light of frequency less than threshold frequency can not emit electrons; whatever be the intensity of incident light. Einstein also proposed that electromagnetic radiation is quantised.If photoelectrons are ejected from a surface when light of wavelength λ1 = 550 nm is incident on it. The stopping potential for such electrons is Vs =0.19 . Suppose the radiation of wavelength λ2 = 190 nm is incident on the surface.Q. Calculate the stopping potential Vs2 of the surface.a)4.47b)3.16c)2.76d)5.28Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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