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A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.
Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.
Q. The intermediate image formed by the objective of a compound microscope is
  • a)
    real, inverted and magnified
  • b)
    real, erect and magnified
  • c)
    virtual, erect and magnified
  • d)
    virtual, inverted and magnified
Correct answer is option 'A'. Can you explain this answer?
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The intermediate image formed by the objective of a compound microscope is real, inverted and magnified.
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Objective Lens
The objective lens of a compound microscope is responsible for collecting and magnifying the light from the object being observed. In this case, the objective lens has a focal length of 2.0 cm.

Eyepiece Lens
The eyepiece lens of a compound microscope is responsible for further magnifying the intermediate image formed by the objective lens and projecting it into the observer's eye. In this case, the eyepiece lens has a focal length of 6.25 cm.

Distance between Lenses
The objective lens and eyepiece lens are separated by a distance of 15 cm. This distance is important for the proper functioning of the compound microscope.

Magnification of the Objective Lens
The magnification produced by the objective lens can be calculated using the formula:

mo = -do/di

where do is the object distance and di is the image distance. Since the object is placed at the least distance of distinct vision (25 cm) from the eye, the image distance is equal to the distance between the lenses (15 cm). Plugging in the values, we get:

mo = -25 cm / 15 cm = -1.67

The negative sign indicates that the image formed by the objective lens is inverted.

Magnification of the Eyepiece Lens
The magnification produced by the eyepiece lens can be calculated using the formula:

me = 1 + do / fe

where do is the object distance and fe is the focal length of the eyepiece lens. Since the object is placed at the least distance of distinct vision (25 cm) from the eye, the object distance is equal to the distance between the lenses (15 cm). Plugging in the values, we get:

me = 1 + 15 cm / 6.25 cm = 3.4

Total Magnification
The total magnification of the compound microscope is given by the product of the magnification of the objective lens and the magnification of the eyepiece lens:

m = mo x me = -1.67 x 3.4 ≈ -5.66

The negative sign indicates that the final image formed by the compound microscope is inverted.

Conclusion
Based on the calculations, we can conclude that the intermediate image formed by the objective lens of the compound microscope is real, inverted, and magnified.
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A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The intermediate image formed by the objective of a compound microscope isa)real, inverted and magnifiedb)real, erect and magnifiedc)virtual, erect and magnifiedd)virtual, inverted and magnifiedCorrect answer is option 'A'. Can you explain this answer?
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A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The intermediate image formed by the objective of a compound microscope isa)real, inverted and magnifiedb)real, erect and magnifiedc)virtual, erect and magnifiedd)virtual, inverted and magnifiedCorrect answer is option 'A'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The intermediate image formed by the objective of a compound microscope isa)real, inverted and magnifiedb)real, erect and magnifiedc)virtual, erect and magnifiedd)virtual, inverted and magnifiedCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A compound microscope is an optical instrument used for observing highly magnified images of tiny objects. Magnifying power of a compound microscope is defined as the ratio of the angle subtended at the eye by the final image to the angle subtended at the eye by the object, when both the final image and the objects are situated at the least distance of distinct vision from the eye. It can be given that: m=me x mo, where me is the magnification produced by the eye lens and mo is the magnification produced by the objective lens.Consider a compound microscope that consists of an objective lens of focal length 2.0 cm and an eyepiece of focal length 6.25 cm separated by a distance of 15 cm.Q. The intermediate image formed by the objective of a compound microscope isa)real, inverted and magnifiedb)real, erect and magnifiedc)virtual, erect and magnifiedd)virtual, inverted and magnifiedCorrect answer is option 'A'. Can you explain this answer?.
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