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Entropy is a measure of degree of randomness. Entropy is directly proportional to temperature. Every system tries to acquire maximum state of randomness or disorder. Entropy is a measure of unavailable energy. Unavailable energy = Entropy × Temperature The ratio of Entropy of Vaporization and boiling point of a substance remains almost constant. Answer the given below questions (i) to (iv).
Q. The sign of ΔS in the reaction, N2(g) + O2(g) → 2NO(g) is:
- a)+ve
- b)–ve
- c)Zero
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Entropy is a measure of degree of randomness. Entropy is directly prop...
It is an endothermic pressure. It will spontaneous only if ΔS = +ve.
Most Upvoted Answer
Entropy is a measure of degree of randomness. Entropy is directly prop...
Explanation:
Let's understand the given reaction: N2(g) + O2(g) → 2NO(g)
In this reaction, nitrogen gas (N2) and oxygen gas (O2) react to form nitrogen monoxide gas (NO). The stoichiometric coefficient in front of each compound represents the number of moles of that compound involved in the reaction.
To determine the sign of ΔS (change in entropy) for this reaction, we need to consider the number of gaseous moles before and after the reaction.
Before the reaction:
N2(g) + O2(g) → 2NO(g)
There are 1 mole of N2 and 1 mole of O2, so the total number of gaseous moles is 1 + 1 = 2.
After the reaction:
N2(g) + O2(g) → 2NO(g)
There are 2 moles of NO, so the total number of gaseous moles is 2.
Since the number of gaseous moles has increased from 2 to 2, there is no change in the number of gaseous moles. Therefore, the change in entropy (ΔS) for this reaction is zero.
Hence, the answer is option 'A' (zero).
Summary:
- The given reaction is N2(g) + O2(g) → 2NO(g).
- To determine the sign of ΔS (change in entropy), we consider the number of gaseous moles before and after the reaction.
- The number of gaseous moles does not change from 2 to 2, so the change in entropy (ΔS) is zero.
- Therefore, the answer is option 'A' (zero).
Let's understand the given reaction: N2(g) + O2(g) → 2NO(g)
In this reaction, nitrogen gas (N2) and oxygen gas (O2) react to form nitrogen monoxide gas (NO). The stoichiometric coefficient in front of each compound represents the number of moles of that compound involved in the reaction.
To determine the sign of ΔS (change in entropy) for this reaction, we need to consider the number of gaseous moles before and after the reaction.
Before the reaction:
N2(g) + O2(g) → 2NO(g)
There are 1 mole of N2 and 1 mole of O2, so the total number of gaseous moles is 1 + 1 = 2.
After the reaction:
N2(g) + O2(g) → 2NO(g)
There are 2 moles of NO, so the total number of gaseous moles is 2.
Since the number of gaseous moles has increased from 2 to 2, there is no change in the number of gaseous moles. Therefore, the change in entropy (ΔS) for this reaction is zero.
Hence, the answer is option 'A' (zero).
Summary:
- The given reaction is N2(g) + O2(g) → 2NO(g).
- To determine the sign of ΔS (change in entropy), we consider the number of gaseous moles before and after the reaction.
- The number of gaseous moles does not change from 2 to 2, so the change in entropy (ΔS) is zero.
- Therefore, the answer is option 'A' (zero).
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Entropy is a measure of degree of randomness. Entropy is directly prop...
Which of the following has s= -ve
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Entropy is a measure of degree of randomness. Entropy is directly proportional to temperature. Every system tries to acquire maximum state of randomness or disorder. Entropy is a measure of unavailable energy. Unavailable energy = Entropy × Temperature The ratio of Entropy of Vaporization and boiling point of a substance remains almost constant. Answer the given below questions (i) to (iv).Q. The sign ofΔS in the reaction, N2(g) + O2(g) → 2NO(g) is:a)+veb)–vec)Zerod)None of theseCorrect answer is option 'A'. Can you explain this answer?
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Entropy is a measure of degree of randomness. Entropy is directly proportional to temperature. Every system tries to acquire maximum state of randomness or disorder. Entropy is a measure of unavailable energy. Unavailable energy = Entropy × Temperature The ratio of Entropy of Vaporization and boiling point of a substance remains almost constant. Answer the given below questions (i) to (iv).Q. The sign ofΔS in the reaction, N2(g) + O2(g) → 2NO(g) is:a)+veb)–vec)Zerod)None of theseCorrect answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Entropy is a measure of degree of randomness. Entropy is directly proportional to temperature. Every system tries to acquire maximum state of randomness or disorder. Entropy is a measure of unavailable energy. Unavailable energy = Entropy × Temperature The ratio of Entropy of Vaporization and boiling point of a substance remains almost constant. Answer the given below questions (i) to (iv).Q. The sign ofΔS in the reaction, N2(g) + O2(g) → 2NO(g) is:a)+veb)–vec)Zerod)None of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Entropy is a measure of degree of randomness. Entropy is directly proportional to temperature. Every system tries to acquire maximum state of randomness or disorder. Entropy is a measure of unavailable energy. Unavailable energy = Entropy × Temperature The ratio of Entropy of Vaporization and boiling point of a substance remains almost constant. Answer the given below questions (i) to (iv).Q. The sign ofΔS in the reaction, N2(g) + O2(g) → 2NO(g) is:a)+veb)–vec)Zerod)None of theseCorrect answer is option 'A'. Can you explain this answer?.
Entropy is a measure of degree of randomness. Entropy is directly proportional to temperature. Every system tries to acquire maximum state of randomness or disorder. Entropy is a measure of unavailable energy. Unavailable energy = Entropy × Temperature The ratio of Entropy of Vaporization and boiling point of a substance remains almost constant. Answer the given below questions (i) to (iv).Q. The sign ofΔS in the reaction, N2(g) + O2(g) → 2NO(g) is:a)+veb)–vec)Zerod)None of theseCorrect answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Entropy is a measure of degree of randomness. Entropy is directly proportional to temperature. Every system tries to acquire maximum state of randomness or disorder. Entropy is a measure of unavailable energy. Unavailable energy = Entropy × Temperature The ratio of Entropy of Vaporization and boiling point of a substance remains almost constant. Answer the given below questions (i) to (iv).Q. The sign ofΔS in the reaction, N2(g) + O2(g) → 2NO(g) is:a)+veb)–vec)Zerod)None of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Entropy is a measure of degree of randomness. Entropy is directly proportional to temperature. Every system tries to acquire maximum state of randomness or disorder. Entropy is a measure of unavailable energy. Unavailable energy = Entropy × Temperature The ratio of Entropy of Vaporization and boiling point of a substance remains almost constant. Answer the given below questions (i) to (iv).Q. The sign ofΔS in the reaction, N2(g) + O2(g) → 2NO(g) is:a)+veb)–vec)Zerod)None of theseCorrect answer is option 'A'. Can you explain this answer?.
Solutions for Entropy is a measure of degree of randomness. Entropy is directly proportional to temperature. Every system tries to acquire maximum state of randomness or disorder. Entropy is a measure of unavailable energy. Unavailable energy = Entropy × Temperature The ratio of Entropy of Vaporization and boiling point of a substance remains almost constant. Answer the given below questions (i) to (iv).Q. The sign ofΔS in the reaction, N2(g) + O2(g) → 2NO(g) is:a)+veb)–vec)Zerod)None of theseCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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