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The pressure inside a soap bubble of 50 mm diameter is 25 N/m² above the atmospheric pressure. The surface tension in soap film would be
  • a)
    0.156 N/m
  • b)
    0.312 N/m
  • c)
    0.624 N/m
  • d)
    0.078 N/m
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The pressure inside a soap bubble of 50 mm diameter is 25 N/m² above ...
Pressure intensity inside a soap bubble,
p = 4? /r
? = pr/4 = 25 x 25 x 10
= 0.15625 N/m
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Most Upvoted Answer
The pressure inside a soap bubble of 50 mm diameter is 25 N/m² above ...
Given information:
Diameter of the soap bubble = 50 mm = 0.05 m
Pressure inside the bubble = 25 N/m² above atmospheric pressure

To find: Surface tension in the soap film

Formula:
The pressure inside a soap bubble is given by the Laplace's law:
P = 4T/r,
where P is the pressure inside the bubble, T is the surface tension of the soap film, and r is the radius of the bubble.

Step-by-step solution:

1. Convert the diameter of the bubble to radius:
Radius = diameter/2 = 0.05 m/2 = 0.025 m.

2. Substitute the values into the Laplace's law:
25 N/m² = 4T/0.025 m.

3. Solve for T:
T = (25 N/m² * 0.025 m)/4.

T = 0.625 N/m.

Therefore, the surface tension in the soap film is 0.625 N/m.

Answer:
The correct option is A) 0.156 N/m.
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The pressure inside a soap bubble of 50 mm diameter is 25 N/m² above the atmospheric pressure. The surface tension in soap film would bea)0.156 N/mb)0.312 N/mc)0.624 N/md)0.078 N/mCorrect answer is option 'A'. Can you explain this answer?
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