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A 5 m long vertical tube having cross sectional area 200 cm^2 is placed in water. It is filled with 15°C water, with the bottom closed and the top open to 100 kPa atmosphere. How much water is present in the tube?
- a)99.9 kg
- b)109.9 kg
- c)89.9 kg
- d)79.9 kg
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A 5 m long vertical tube having cross sectional area 200 cm^2 is pla...
M = ρ V = V/v = AH/v
View all questions of this test
= 200 × 10^(−4) × 5/0.001001 = 99.9 kg.
Most Upvoted Answer
A 5 m long vertical tube having cross sectional area 200 cm^2 is pla...
Given data:
Length of the tube (L) = 5 m
Cross-sectional area of the tube (A) = 200 cm^2 = 0.02 m^2
Temperature of water (T) = 15°C
Pressure at the top of the tube (P) = 100 kPa
Step 1: Converting the units
Since the given values are in different units, we need to convert them into a common unit.
Area (A) = 0.02 m^2
Length (L) = 5 m
Temperature (T) = 15°C = 15 + 273 = 288 K
Pressure (P) = 100 kPa
Step 2: Calculating the density of water
To find the amount of water in the tube, we need to calculate the mass of water. The mass of water can be calculated using the density formula:
Density (ρ) = mass (m) / volume (V)
The density of water can be taken as 1000 kg/m^3.
Step 3: Calculating the volume of water
Volume (V) = Area (A) x Length (L)
V = 0.02 m^2 x 5 m = 0.1 m^3
Step 4: Calculating the mass of water
Mass (m) = Density (ρ) x Volume (V)
m = 1000 kg/m^3 x 0.1 m^3 = 100 kg
Step 5: Converting the mass into kilograms
Since the options are given in kilograms, we need to convert the mass from grams to kilograms.
Mass (m) = 100 kg = 100 x 1000 g = 100000 g = 100 kg
Step 6: Comparing the result with the given options
The correct answer is given as option 'A' which is 99.9 kg. Since our calculated mass is 100 kg which is closest to 99.9 kg, the correct answer is option 'A'.
Therefore, the amount of water present in the tube is 99.9 kg.
Length of the tube (L) = 5 m
Cross-sectional area of the tube (A) = 200 cm^2 = 0.02 m^2
Temperature of water (T) = 15°C
Pressure at the top of the tube (P) = 100 kPa
Step 1: Converting the units
Since the given values are in different units, we need to convert them into a common unit.
Area (A) = 0.02 m^2
Length (L) = 5 m
Temperature (T) = 15°C = 15 + 273 = 288 K
Pressure (P) = 100 kPa
Step 2: Calculating the density of water
To find the amount of water in the tube, we need to calculate the mass of water. The mass of water can be calculated using the density formula:
Density (ρ) = mass (m) / volume (V)
The density of water can be taken as 1000 kg/m^3.
Step 3: Calculating the volume of water
Volume (V) = Area (A) x Length (L)
V = 0.02 m^2 x 5 m = 0.1 m^3
Step 4: Calculating the mass of water
Mass (m) = Density (ρ) x Volume (V)
m = 1000 kg/m^3 x 0.1 m^3 = 100 kg
Step 5: Converting the mass into kilograms
Since the options are given in kilograms, we need to convert the mass from grams to kilograms.
Mass (m) = 100 kg = 100 x 1000 g = 100000 g = 100 kg
Step 6: Comparing the result with the given options
The correct answer is given as option 'A' which is 99.9 kg. Since our calculated mass is 100 kg which is closest to 99.9 kg, the correct answer is option 'A'.
Therefore, the amount of water present in the tube is 99.9 kg.
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A 5 m long vertical tube having cross sectional area 200 cm^2 is placed in water. It is filled with 15°C water, with the bottom closed and the top open to 100 kPa atmosphere. How much water is present in the tube?a)99.9 kgb)109.9 kgc)89.9 kgd)79.9 kgCorrect answer is option 'A'. Can you explain this answer?
Question Description
A 5 m long vertical tube having cross sectional area 200 cm^2 is placed in water. It is filled with 15°C water, with the bottom closed and the top open to 100 kPa atmosphere. How much water is present in the tube?a)99.9 kgb)109.9 kgc)89.9 kgd)79.9 kgCorrect answer is option 'A'. Can you explain this answer? for Railways 2024 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about A 5 m long vertical tube having cross sectional area 200 cm^2 is placed in water. It is filled with 15°C water, with the bottom closed and the top open to 100 kPa atmosphere. How much water is present in the tube?a)99.9 kgb)109.9 kgc)89.9 kgd)79.9 kgCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Railways 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 5 m long vertical tube having cross sectional area 200 cm^2 is placed in water. It is filled with 15°C water, with the bottom closed and the top open to 100 kPa atmosphere. How much water is present in the tube?a)99.9 kgb)109.9 kgc)89.9 kgd)79.9 kgCorrect answer is option 'A'. Can you explain this answer?.
A 5 m long vertical tube having cross sectional area 200 cm^2 is placed in water. It is filled with 15°C water, with the bottom closed and the top open to 100 kPa atmosphere. How much water is present in the tube?a)99.9 kgb)109.9 kgc)89.9 kgd)79.9 kgCorrect answer is option 'A'. Can you explain this answer? for Railways 2024 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about A 5 m long vertical tube having cross sectional area 200 cm^2 is placed in water. It is filled with 15°C water, with the bottom closed and the top open to 100 kPa atmosphere. How much water is present in the tube?a)99.9 kgb)109.9 kgc)89.9 kgd)79.9 kgCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Railways 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 5 m long vertical tube having cross sectional area 200 cm^2 is placed in water. It is filled with 15°C water, with the bottom closed and the top open to 100 kPa atmosphere. How much water is present in the tube?a)99.9 kgb)109.9 kgc)89.9 kgd)79.9 kgCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A 5 m long vertical tube having cross sectional area 200 cm^2 is placed in water. It is filled with 15°C water, with the bottom closed and the top open to 100 kPa atmosphere. How much water is present in the tube?a)99.9 kgb)109.9 kgc)89.9 kgd)79.9 kgCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Railways.
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