A tank containing air is stirred by a paddle wheel. The work input to...
This is a case of a constant volume process or an isochoric process. In an irreversible constant volume process, the system doesn’t perform work on the surrounding at the expense of its normal energy. By performing work on the system, the temperature can be raised.
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A tank containing air is stirred by a paddle wheel. The work input to...
This is a case of a constant volume process or an isochoric process. In an irreversible constant volume process, the system doesn’t perform work on the surrounding at the expense of its normal energy. By performing work on the system, the temperature can be raised.
A tank containing air is stirred by a paddle wheel. The work input to...
Calculation of External Work Done
- The external work done by the system can be calculated using the first law of thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system.
- Mathematically, the equation can be written as: ΔU = Q - W, where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system.
Given Data
- Work input to the paddle wheel (W) = 9000 kJ
- Heat transferred to the surroundings (Q) = 3000 kJ
Calculation
- Since the work input to the paddle wheel is considered as work done by the system, the work done by the system (W) is 9000 kJ.
- Heat transferred to the surroundings (Q) is 3000 kJ.
- Using the first law of thermodynamics equation, we can calculate the change in internal energy (ΔU) as follows: ΔU = Q - W
- ΔU = 3000 kJ - 9000 kJ = -6000 kJ
Conclusion
- The negative sign indicates that the internal energy of the system has decreased by 6000 kJ. Since the external work done by the system is equal to the change in internal energy, the external work done by the system is zero (0 kJ).