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A slider moves with uniform velocity ‘v’ on a revolving link of length ‘l’ with angular velocity ‘ω’. The Coriolis acceleration component of point on the slider relative to a coincident point on the link is equal to
  • a)
    ωv parallel to the link
  • b)
    2ωv perpendicular to the link
  • c)
    ωv perpendicular to the link
  • d)
    2ωv parallel to the link
Correct answer is option 'B'. Can you explain this answer?
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The Coriolis effect is a phenomenon that occurs when an object is moving in a rotating reference frame, such as a revolving link. It causes a deflection in the motion of the object, resulting in an acceleration known as the Coriolis acceleration. In this case, we have a slider moving with a uniform velocity 'v' on a revolving link of length 'l' with angular velocity 'ω'. Let's analyze the situation to understand why the correct answer is option 'B'.

1. Understanding the Coriolis effect:
- The Coriolis effect is a result of the conservation of angular momentum. As the link rotates, it imparts an angular momentum to the slider, causing it to move in a circular path.
- The Coriolis acceleration arises due to the change in velocity of the slider as it moves along the circular path.

2. Determining the direction of the Coriolis acceleration:
- The Coriolis acceleration is always perpendicular to the velocity of the object and the axis of rotation.
- In this case, the slider is moving with velocity 'v' along the revolving link. The velocity vector is tangential to the circular path.
- The axis of rotation is perpendicular to the plane of motion.
- Therefore, the Coriolis acceleration will be perpendicular to both the velocity vector and the axis of rotation.

3. Analyzing the options:
a) ωv parallel to the link: This option is incorrect because the Coriolis acceleration is always perpendicular to the axis of rotation, not parallel to it.
b) 2ωv perpendicular to the link: This option is correct because the Coriolis acceleration is indeed perpendicular to both the velocity vector and the axis of rotation.
c) ωv perpendicular to the link: This option is incorrect because the magnitude of the Coriolis acceleration is not equal to the angular velocity 'ω', but rather to twice the angular velocity '2ω'.
d) 2ωv parallel to the link: This option is incorrect because the Coriolis acceleration is always perpendicular to the axis of rotation, not parallel to it.

Therefore, the correct answer is option 'B' - 2ωv perpendicular to the link.
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A slider moves with uniform velocity ‘v’ on a revolving link of length ‘l’ with angular velocity ‘ω’. The Coriolis acceleration component of point on the slider relative to a coincident point on the link is equal toa)ωv parallel to the linkb)2ωv perpendicular to the linkc)ωv perpendicular to the linkd)2ωv parallel to the linkCorrect answer is option 'B'. Can you explain this answer?
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A slider moves with uniform velocity ‘v’ on a revolving link of length ‘l’ with angular velocity ‘ω’. The Coriolis acceleration component of point on the slider relative to a coincident point on the link is equal toa)ωv parallel to the linkb)2ωv perpendicular to the linkc)ωv perpendicular to the linkd)2ωv parallel to the linkCorrect answer is option 'B'. Can you explain this answer? for Railways 2024 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about A slider moves with uniform velocity ‘v’ on a revolving link of length ‘l’ with angular velocity ‘ω’. The Coriolis acceleration component of point on the slider relative to a coincident point on the link is equal toa)ωv parallel to the linkb)2ωv perpendicular to the linkc)ωv perpendicular to the linkd)2ωv parallel to the linkCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Railways 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A slider moves with uniform velocity ‘v’ on a revolving link of length ‘l’ with angular velocity ‘ω’. The Coriolis acceleration component of point on the slider relative to a coincident point on the link is equal toa)ωv parallel to the linkb)2ωv perpendicular to the linkc)ωv perpendicular to the linkd)2ωv parallel to the linkCorrect answer is option 'B'. Can you explain this answer?.
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