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A Person Holds a Bucket by Applying a 10n Force. He Then Moves a Horizontal Distance of 5m and Climbs up a Vertical Distance of 10m. Find out the total work done by him?
    Correct answer is '100'. Can you explain this answer?
    Verified Answer
    A Person Holds a Bucket by Applying a 10n Force. He Then Moves a Horiz...
    s = 5m, F = 10N, and θ = 90° 
    Work done is given by, W1 = F scos θ = 10 × 5 × cos 90° = 0
    In the case of vertical motion, the angle between force and displacement is 0°
    Here, F = 10N, s = 10m, and θ=0° So, work done, W2 = 10 × 10 × cos0 = 100J
    Therefore, the total work done = W1 + W2 = 100J.
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    Most Upvoted Answer
    A Person Holds a Bucket by Applying a 10n Force. He Then Moves a Horiz...
    Given Information:
    - Force applied: 10 N
    - Horizontal distance moved: 5 m
    - Vertical distance climbed: 10 m

    Work Done:
    Work done is defined as the product of the force applied and the distance moved in the direction of the force. In this case, there are two components of work done - the work done in moving horizontally and the work done in climbing vertically.

    Work Done Horizontally:
    The work done horizontally can be calculated using the formula:
    Work done horizontally = Force × Distance
    = 10 N × 5 m
    = 50 N·m
    = 50 J

    Work Done Vertically:
    The work done vertically can be calculated using the formula:
    Work done vertically = Force × Distance
    = 10 N × 10 m
    = 100 N·m
    = 100 J

    Total Work Done:
    To find the total work done, we need to add the work done horizontally and the work done vertically.
    Total work done = Work done horizontally + Work done vertically
    = 50 J + 100 J
    = 150 J

    Correcting the Answer:
    The correct answer is 150 J, not 100 J as stated.
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    A Person Holds a Bucket by Applying a 10n Force. He Then Moves a Horizontal Distance of 5m and Climbs up a Vertical Distance of 10m. Find out the total work done by him?Correct answer is '100'. Can you explain this answer?
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