The equilibrium constant for the reaction co+H2O=co2+H2 at a certain t...
As we know concentration is mol/V we do 1/2 so Initial concentration as 0.5,0.5,0 and 0 of CO, H2O, H2 and CO2 respectively and equillibrum conc as 0.5-x,0.5-x, x and x of CO H2O CO2 H2 respectively after putting formula 2.2=(x)(x)/(0.5-x)(0.5-x) and using quadratic equation we get two answers of x 0.53 and 0.3 as the conc of reactants must be greater than x to get possitive answer 0.3 is right value and through that we get 0.3 0.3 0.2 and 0.2 equillibrumic concentration of H2 CO2 and CO H2O respectively .hope this answers the question .
The equilibrium constant for the reaction co+H2O=co2+H2 at a certain t...
Explanation:
The given reaction is: CO + H2O ⇌ CO2 + H2
The equilibrium constant (K) is defined as the ratio of the product concentrations to the reactant concentrations, each raised to the power of their stoichiometric coefficients. In this case, the equilibrium constant is given as 2.2.
To determine the concentrations of all the substances when the reaction reaches equilibrium, we need to consider the initial concentrations and the stoichiometry of the reaction.
Initial conditions:
- Initial concentration of CO (COCO) = 1 mole / 2 L = 0.5 M
- Initial concentration of H2O (H2OH2O) = 1 mole / 2 L = 0.5 M
- Initial concentration of CO2 (COCO2) = 0 M
- Initial concentration of H2 (H2H2) = 0 M
At equilibrium:
Let's assume that 'x' moles of CO and H2O have reacted to form CO2 and H2. Therefore, the change in concentration for CO and H2O will be -x, and the change in concentration for CO2 and H2 will be +x.
- Concentration of CO (COCO) = 0.5 - x M
- Concentration of H2O (H2OH2O) = 0.5 - x M
- Concentration of CO2 (COCO2) = x M
- Concentration of H2 (H2H2) = x M
The equilibrium constant (K) is given as 2.2, which means:
K = [COCO2] * [H2H2] / [COCO] * [H2OH2O]
2.2 = (x) * (x) / (0.5 - x) * (0.5 - x)
Simplifying the equation:
2.2 = x^2 / (0.5 - x)^2
2.2 * (0.5 - x)^2 = x^2
2.2 * (0.25 - x + x^2) = x^2
0.55 - 2.2x + 2.2x^2 = x^2
2.2x^2 - x^2 + 2.2x - 2.2x - 0.55 = 0
1.2x^2 - 0.55 = 0
1.2x^2 = 0.55
x^2 = 0.55 / 1.2
x^2 = 0.4583
x = √(0.4583)
x ≈ 0.677 moles
Concentrations at equilibrium:
- Concentration of CO (COCO) = 0.5 - 0.677 M ≈ -0.177 M (negative value indicates that the reactant is consumed)
- Concentration of H2O (H2OH2O) = 0.5 - 0.677 M ≈ -0.177 M (negative value indicates that the reactant is consumed)
- Concentration of CO2 (COCO2) =
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.