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The equilibrium constant Kp for the reaction H2 +CO2¬H20 +CO is 4at 1660C .initially 0.80 mole of h2 & 0.80 mole of CO2 are injected into 5L flask .What is the equilibrium concentration of CO2? 1)0.533M. 2)0.0534M. 3)5.34M. 4)none of this.ans is 2 one .can any one explain how?
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The equilibrium constant Kp for the reaction H2 +CO2¬H20 +CO is 4at 16...
We cannot complete this problem as the sentence "initially 0.80 mole of h2" is incomplete. We need to know the initial moles of CO2 and any other relevant information to solve this problem.
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The equilibrium constant Kp for the reaction H2 +CO2¬H20 +CO is 4at 16...
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The equilibrium constant Kp for the reaction H2 +CO2¬H20 +CO is 4at 1660C .initially 0.80 mole of h2 & 0.80 mole of CO2 are injected into 5L flask .What is the equilibrium concentration of CO2? 1)0.533M. 2)0.0534M. 3)5.34M. 4)none of this.ans is 2 one .can any one explain how?
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The equilibrium constant Kp for the reaction H2 +CO2¬H20 +CO is 4at 1660C .initially 0.80 mole of h2 & 0.80 mole of CO2 are injected into 5L flask .What is the equilibrium concentration of CO2? 1)0.533M. 2)0.0534M. 3)5.34M. 4)none of this.ans is 2 one .can any one explain how? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The equilibrium constant Kp for the reaction H2 +CO2¬H20 +CO is 4at 1660C .initially 0.80 mole of h2 & 0.80 mole of CO2 are injected into 5L flask .What is the equilibrium concentration of CO2? 1)0.533M. 2)0.0534M. 3)5.34M. 4)none of this.ans is 2 one .can any one explain how? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equilibrium constant Kp for the reaction H2 +CO2¬H20 +CO is 4at 1660C .initially 0.80 mole of h2 & 0.80 mole of CO2 are injected into 5L flask .What is the equilibrium concentration of CO2? 1)0.533M. 2)0.0534M. 3)5.34M. 4)none of this.ans is 2 one .can any one explain how?.
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