Question Description
The equilibrium constant for the reactionCO(g) + H2O(g)CO2(g) + H2(g) is 3 at 500 K. In a 2 litre vessel 60 gm of water gas [equimolar mixture of CO(g) and H2(g)] and 90 gm of steam is initially taken.What is the equilibrium concentration of H2(g) at equilibrium (mole/L) ?a)1.75b)3.5c)1.5d)0.75Correct answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The equilibrium constant for the reactionCO(g) + H2O(g)CO2(g) + H2(g) is 3 at 500 K. In a 2 litre vessel 60 gm of water gas [equimolar mixture of CO(g) and H2(g)] and 90 gm of steam is initially taken.What is the equilibrium concentration of H2(g) at equilibrium (mole/L) ?a)1.75b)3.5c)1.5d)0.75Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equilibrium constant for the reactionCO(g) + H2O(g)CO2(g) + H2(g) is 3 at 500 K. In a 2 litre vessel 60 gm of water gas [equimolar mixture of CO(g) and H2(g)] and 90 gm of steam is initially taken.What is the equilibrium concentration of H2(g) at equilibrium (mole/L) ?a)1.75b)3.5c)1.5d)0.75Correct answer is option 'B'. Can you explain this answer?.

Solutions for The equilibrium constant for the reactionCO(g) + H2O(g)CO2(g) + H2(g) is 3 at 500 K. In a 2 litre vessel 60 gm of water gas [equimolar mixture of CO(g) and H2(g)] and 90 gm of steam is initially taken.What is the equilibrium concentration of H2(g) at equilibrium (mole/L) ?a)1.75b)3.5c)1.5d)0.75Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11. Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.

Here you can find the meaning of The equilibrium constant for the reactionCO(g) + H2O(g)CO2(g) + H2(g) is 3 at 500 K. In a 2 litre vessel 60 gm of water gas [equimolar mixture of CO(g) and H2(g)] and 90 gm of steam is initially taken.What is the equilibrium concentration of H2(g) at equilibrium (mole/L) ?a)1.75b)3.5c)1.5d)0.75Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The equilibrium constant for the reactionCO(g) + H2O(g)CO2(g) + H2(g) is 3 at 500 K. In a 2 litre vessel 60 gm of water gas [equimolar mixture of CO(g) and H2(g)] and 90 gm of steam is initially taken.What is the equilibrium concentration of H2(g) at equilibrium (mole/L) ?a)1.75b)3.5c)1.5d)0.75Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The equilibrium constant for the reactionCO(g) + H2O(g)CO2(g) + H2(g) is 3 at 500 K. In a 2 litre vessel 60 gm of water gas [equimolar mixture of CO(g) and H2(g)] and 90 gm of steam is initially taken.What is the equilibrium concentration of H2(g) at equilibrium (mole/L) ?a)1.75b)3.5c)1.5d)0.75Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The equilibrium constant for the reactionCO(g) + H2O(g)CO2(g) + H2(g) is 3 at 500 K. In a 2 litre vessel 60 gm of water gas [equimolar mixture of CO(g) and H2(g)] and 90 gm of steam is initially taken.What is the equilibrium concentration of H2(g) at equilibrium (mole/L) ?a)1.75b)3.5c)1.5d)0.75Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The equilibrium constant for the reactionCO(g) + H2O(g)CO2(g) + H2(g) is 3 at 500 K. In a 2 litre vessel 60 gm of water gas [equimolar mixture of CO(g) and H2(g)] and 90 gm of steam is initially taken.What is the equilibrium concentration of H2(g) at equilibrium (mole/L) ?a)1.75b)3.5c)1.5d)0.75Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 11 tests.