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Vessel contains mixture of milk and water in ratio 22:3 and 20 litre of mixture taken out and replaced with 16 litre of pure milk so water become 11 1/9 % of resulting mixture.if vessel filled 88% initially find total capacity of vessel.? Banking Exams Question?
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Vessel contains mixture of milk and water in ratio 22:3 and 20 litre o...
Problem: A vessel contains a mixture of milk and water in the ratio 22:3. 20 litres of the mixture is taken out and replaced with 16 litres of pure milk. As a result, water becomes 11 1/9% of the resulting mixture. If the vessel is filled to 88% initially, find the total capacity of the vessel.
Solution:
Let the initial capacity of the vessel be x litres.
Initially, the vessel is filled to 88%, so the quantity of mixture in the vessel = 0.88x litres.
Given, the ratio of milk and water in the mixture = 22:3
So, let the quantity of milk = 22y and the quantity of water = 3y.
Hence, the quantity of mixture = 22y + 3y = 25y.
Therefore, the percentage of milk in the mixture = (22y / 25y) × 100% = 88%.
And, the percentage of water in the mixture = (3y / 25y) × 100% = 12%.
Now, 20 litres of the mixture is taken out and replaced with 16 litres of pure milk.
Let the final quantity of water in the mixture be z litres.
So, the quantity of milk in the mixture will remain the same, i.e. 22y litres.
The quantity of mixture left in the vessel after taking out 20 litres = (0.88x - 20) litres.
So, the quantity of water in the mixture left in the vessel = 0.12(0.88x - 20) = 0.1056x - 2.4 litres.
The quantity of water added to the mixture = (z - 3y) litres
And, the quantity of milk added to the mixture = 16 litres.
After the replacement, the ratio of milk and water in the mixture = (22y + 16) : (z - 3y)
Given, water becomes 11 1/9% of the resulting mixture.
So, the percentage of water in the mixture after the replacement = 11 1/9% = (1/9) × 100/1% + 11% = 100/9 + 11% = 200/9%
Therefore, we get the following equation:
(200/9) = [(z - 3y) / (22y + 16 + z - 3y)] × 100%
On simplifying, we get:
z = (297/20)y + 80
Now, the quantity of water added to the mixture = (z - 3y) litres
So, (z - 3y) litres = (297/20)y + 80 - 3y litres = (197y/20) + 80 litres.
On equating the above equation with the quantity of water added, we get:
(197y/20) + 80 = (0.1056x - 2.4) litres
On simplifying, we get:
y = (1/25)(0.1056x - 245)
Also, from the initial mixture, we get:
(22y + 3y) litres = 0.88x litres
On substituting the value of y, we get:
Solution:
Let the initial capacity of the vessel be x litres.
Initially, the vessel is filled to 88%, so the quantity of mixture in the vessel = 0.88x litres.
Given, the ratio of milk and water in the mixture = 22:3
So, let the quantity of milk = 22y and the quantity of water = 3y.
Hence, the quantity of mixture = 22y + 3y = 25y.
Therefore, the percentage of milk in the mixture = (22y / 25y) × 100% = 88%.
And, the percentage of water in the mixture = (3y / 25y) × 100% = 12%.
Now, 20 litres of the mixture is taken out and replaced with 16 litres of pure milk.
Let the final quantity of water in the mixture be z litres.
So, the quantity of milk in the mixture will remain the same, i.e. 22y litres.
The quantity of mixture left in the vessel after taking out 20 litres = (0.88x - 20) litres.
So, the quantity of water in the mixture left in the vessel = 0.12(0.88x - 20) = 0.1056x - 2.4 litres.
The quantity of water added to the mixture = (z - 3y) litres
And, the quantity of milk added to the mixture = 16 litres.
After the replacement, the ratio of milk and water in the mixture = (22y + 16) : (z - 3y)
Given, water becomes 11 1/9% of the resulting mixture.
So, the percentage of water in the mixture after the replacement = 11 1/9% = (1/9) × 100/1% + 11% = 100/9 + 11% = 200/9%
Therefore, we get the following equation:
(200/9) = [(z - 3y) / (22y + 16 + z - 3y)] × 100%
On simplifying, we get:
z = (297/20)y + 80
Now, the quantity of water added to the mixture = (z - 3y) litres
So, (z - 3y) litres = (297/20)y + 80 - 3y litres = (197y/20) + 80 litres.
On equating the above equation with the quantity of water added, we get:
(197y/20) + 80 = (0.1056x - 2.4) litres
On simplifying, we get:
y = (1/25)(0.1056x - 245)
Also, from the initial mixture, we get:
(22y + 3y) litres = 0.88x litres
On substituting the value of y, we get:
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Vessel contains mixture of milk and water in ratio 22:3 and 20 litre of mixture taken out and replaced with 16 litre of pure milk so water become 11 1/9 % of resulting mixture.if vessel filled 88% initially find total capacity of vessel.? Banking Exams Question?
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Vessel contains mixture of milk and water in ratio 22:3 and 20 litre of mixture taken out and replaced with 16 litre of pure milk so water become 11 1/9 % of resulting mixture.if vessel filled 88% initially find total capacity of vessel.? Banking Exams Question? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Vessel contains mixture of milk and water in ratio 22:3 and 20 litre of mixture taken out and replaced with 16 litre of pure milk so water become 11 1/9 % of resulting mixture.if vessel filled 88% initially find total capacity of vessel.? Banking Exams Question? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Vessel contains mixture of milk and water in ratio 22:3 and 20 litre of mixture taken out and replaced with 16 litre of pure milk so water become 11 1/9 % of resulting mixture.if vessel filled 88% initially find total capacity of vessel.? Banking Exams Question?.
Vessel contains mixture of milk and water in ratio 22:3 and 20 litre of mixture taken out and replaced with 16 litre of pure milk so water become 11 1/9 % of resulting mixture.if vessel filled 88% initially find total capacity of vessel.? Banking Exams Question? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Vessel contains mixture of milk and water in ratio 22:3 and 20 litre of mixture taken out and replaced with 16 litre of pure milk so water become 11 1/9 % of resulting mixture.if vessel filled 88% initially find total capacity of vessel.? Banking Exams Question? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Vessel contains mixture of milk and water in ratio 22:3 and 20 litre of mixture taken out and replaced with 16 litre of pure milk so water become 11 1/9 % of resulting mixture.if vessel filled 88% initially find total capacity of vessel.? Banking Exams Question?.
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