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Two poles of the height 15 m and 20 m stand vertically upright on a plane ground. If the distance between their feet is 12 m, find the distance between their tops.
  • a)
    11 m
  • b)
    12 m
  • c)
    13 m
  • d)
    14 m
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Two poles of the height 15 m and 20 m stand vertically upright on a p...
Applying Pythagoras theorem in triangle BDE
BD2 = BE2 + DE2
= 52 + 122
= 25 + 144 = 169
BD = 13m
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Most Upvoted Answer
Two poles of the height 15 m and 20 m stand vertically upright on a p...
Given information:
- Height of the first pole (P1) = 15 m
- Height of the second pole (P2) = 20 m
- Distance between their feet = 12 m

Calculation:
- Let the distance between the tops of the poles be 'x' meters.
- Using the Pythagorean theorem, we can form a right-angled triangle with the two poles and the distance between their tops as the hypotenuse.
- The height of the first pole (15 m) and the height of the second pole (20 m) are the other two sides of the triangle.
- Therefore, by Pythagoras theorem, we have:
x^2 = (20)^2 - (15)^2
x^2 = 400 - 225
x^2 = 175
x = √175
x ≈ 13.23 m

Therefore, the distance between the tops of the two poles is approximately 13.23 meters.

Conclusion:
Hence, the correct option is:
c) 13 m
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Two poles of the height 15 m and 20 m stand vertically upright on a plane ground. If the distance between their feet is 12 m, find the distance between their tops.a)11 mb)12 mc)13 md)14 mCorrect answer is option 'C'. Can you explain this answer?
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