CA Foundation Exam > CA Foundation Questions > Roots of the cubic equation x^3+6x^2-9x+4=0?
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Roots of the cubic equation x^3+6x^2-9x+4=0
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Roots of the cubic equation x^3+6x^2-9x+4=0?
Roots of the cubic equation x^3 + 6x^2 - 9x + 4 = 0
To find the roots of the given cubic equation x^3 + 6x^2 - 9x + 4 = 0, we need to follow the steps mentioned below:
Step 1: Factorize the equation
We can factorize the given cubic equation using the Rational Root Theorem or by trial and error method. After factorizing, we get:
(x-1)(x+2)(x+2) = 0
Step 2: Find the roots
To find the roots of the equation, we need to solve the factors for x. Therefore, we get:
x-1 = 0
x = 1
x+2 = 0
x = -2 (twice)
Hence, the roots of the given cubic equation are x = 1 and x = -2 (twice).
Conclusion
The roots of the given cubic equation x^3 + 6x^2 - 9x + 4 = 0 are x = 1 and x = -2 (twice).
To find the roots of the given cubic equation x^3 + 6x^2 - 9x + 4 = 0, we need to follow the steps mentioned below:
Step 1: Factorize the equation
We can factorize the given cubic equation using the Rational Root Theorem or by trial and error method. After factorizing, we get:
(x-1)(x+2)(x+2) = 0
Step 2: Find the roots
To find the roots of the equation, we need to solve the factors for x. Therefore, we get:
x-1 = 0
x = 1
x+2 = 0
x = -2 (twice)
Hence, the roots of the given cubic equation are x = 1 and x = -2 (twice).
Conclusion
The roots of the given cubic equation x^3 + 6x^2 - 9x + 4 = 0 are x = 1 and x = -2 (twice).
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Roots of the cubic equation x^3+6x^2-9x+4=0?
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Roots of the cubic equation x^3+6x^2-9x+4=0? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Roots of the cubic equation x^3+6x^2-9x+4=0? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Roots of the cubic equation x^3+6x^2-9x+4=0?.
Roots of the cubic equation x^3+6x^2-9x+4=0? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Roots of the cubic equation x^3+6x^2-9x+4=0? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Roots of the cubic equation x^3+6x^2-9x+4=0?.
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