If three dices are thrown then the probability that the sum of the nu...
Solution:
The minimum sum of the numbers on the uppermost faces of three dices = 1+1+1 = 3
The maximum sum of the numbers on the uppermost faces of three dices = 6+6+6 = 18
Let's calculate the probability of getting a sum of 3 or 4.
For getting a sum of 3, there is only one possible combination (1,1,1).
For getting a sum of 4, there are three possible combinations (1,1,2), (1,2,1), and (2,1,1).
Therefore, the probability of getting a sum of 3 or 4 = (1+3)/216 = 1/54
Now, let's calculate the probability of getting a sum of at least 5.
The probability of getting a sum of at least 5 = 1 - probability of getting a sum of 3 or 4
= 1 - 1/54
= 53/54
Therefore, the correct option is (b) 53/54.
If three dices are thrown then the probability that the sum of the nu...
If there dice are drawn, then n(≤) = 6
3 = 216. Let E the sum of the number on their uppermost faces are less than 5 as follows (1, 1, 1),(1, 1, 2),(1, 2, 1),(2, 1, 1)
∴ n(E) = 4
Now, the a probability that the sum of the numbers on their uppermost faces to be at least 5