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If three dices are thrown then the probability that the sum of the numbers on their uppermost faces to be at least 5 is
- a)1/53
- b)53/54
- c)1/54
- d)52/53
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If three dices are thrown then the probability that the sum of the nu...
Solution:
The minimum sum of the numbers on the uppermost faces of three dices = 1+1+1 = 3
The maximum sum of the numbers on the uppermost faces of three dices = 6+6+6 = 18
Let's calculate the probability of getting a sum of 3 or 4.
For getting a sum of 3, there is only one possible combination (1,1,1).
For getting a sum of 4, there are three possible combinations (1,1,2), (1,2,1), and (2,1,1).
Therefore, the probability of getting a sum of 3 or 4 = (1+3)/216 = 1/54
Now, let's calculate the probability of getting a sum of at least 5.
The probability of getting a sum of at least 5 = 1 - probability of getting a sum of 3 or 4
= 1 - 1/54
= 53/54
Therefore, the correct option is (b) 53/54.
The minimum sum of the numbers on the uppermost faces of three dices = 1+1+1 = 3
The maximum sum of the numbers on the uppermost faces of three dices = 6+6+6 = 18
Let's calculate the probability of getting a sum of 3 or 4.
For getting a sum of 3, there is only one possible combination (1,1,1).
For getting a sum of 4, there are three possible combinations (1,1,2), (1,2,1), and (2,1,1).
Therefore, the probability of getting a sum of 3 or 4 = (1+3)/216 = 1/54
Now, let's calculate the probability of getting a sum of at least 5.
The probability of getting a sum of at least 5 = 1 - probability of getting a sum of 3 or 4
= 1 - 1/54
= 53/54
Therefore, the correct option is (b) 53/54.
Community Answer
If three dices are thrown then the probability that the sum of the nu...
If there dice are drawn, then n(≤) = 63 = 216. Let E the sum of the number on their uppermost faces are less than 5 as follows (1, 1, 1),(1, 1, 2),(1, 2, 1),(2, 1, 1)
∴ n(E) = 4
Now, the a probability that the sum of the numbers on their uppermost faces to be at least 5
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If three dices are thrown then the probability that the sum of the numbers on their uppermost faces to be at least 5 isa)1/53b)53/54c)1/54d)52/53Correct answer is option 'B'. Can you explain this answer?
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If three dices are thrown then the probability that the sum of the numbers on their uppermost faces to be at least 5 isa)1/53b)53/54c)1/54d)52/53Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If three dices are thrown then the probability that the sum of the numbers on their uppermost faces to be at least 5 isa)1/53b)53/54c)1/54d)52/53Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If three dices are thrown then the probability that the sum of the numbers on their uppermost faces to be at least 5 isa)1/53b)53/54c)1/54d)52/53Correct answer is option 'B'. Can you explain this answer?.
If three dices are thrown then the probability that the sum of the numbers on their uppermost faces to be at least 5 isa)1/53b)53/54c)1/54d)52/53Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If three dices are thrown then the probability that the sum of the numbers on their uppermost faces to be at least 5 isa)1/53b)53/54c)1/54d)52/53Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If three dices are thrown then the probability that the sum of the numbers on their uppermost faces to be at least 5 isa)1/53b)53/54c)1/54d)52/53Correct answer is option 'B'. Can you explain this answer?.
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