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The reaction, CH₂ = CH-CH₃ + HBr → CH₃CHBr - CH₃ is
- a)Nucleophilic addition
- b)Electrophilic substitution
- c)Electrophilic addition
- d)Free radical addition
Correct answer is option 'C'. Can you explain this answer?
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The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic add...
Answer :
Addition of H−x(x→ Halogens ) on alkenes follows electrophilic addition mechanism.
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The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic add...
Electrophilic Addition
This reaction involves the addition of an electrophile (HBr) to a double bond (CH=CH-CH). The double bond acts as a nucleophile, attacking the electrophile to form a new bond. This type of reaction is known as electrophilic addition.
Mechanism:
1. The double bond in CH=CH-CH acts as a nucleophile and attacks the electrophile HBr.
2. The pi bond breaks as the nucleophile attacks, forming a carbocation intermediate.
3. The Br- ion then attacks the carbocation, forming the final product CHCHBr-CH.
Characteristics of Electrophilic Addition:
- Involves the addition of an electrophile to a double bond.
- Forms a carbocation intermediate.
- Typically occurs with alkenes or alkynes.
- Product is formed by addition of electrophile to the double bond.
In this reaction, the electrophile HBr adds to the double bond in CH=CH-CH, resulting in the formation of CHCHBr-CH. This reaction follows the characteristics of electrophilic addition, making option 'C' the correct answer.
This reaction involves the addition of an electrophile (HBr) to a double bond (CH=CH-CH). The double bond acts as a nucleophile, attacking the electrophile to form a new bond. This type of reaction is known as electrophilic addition.
Mechanism:
1. The double bond in CH=CH-CH acts as a nucleophile and attacks the electrophile HBr.
2. The pi bond breaks as the nucleophile attacks, forming a carbocation intermediate.
3. The Br- ion then attacks the carbocation, forming the final product CHCHBr-CH.
Characteristics of Electrophilic Addition:
- Involves the addition of an electrophile to a double bond.
- Forms a carbocation intermediate.
- Typically occurs with alkenes or alkynes.
- Product is formed by addition of electrophile to the double bond.
In this reaction, the electrophile HBr adds to the double bond in CH=CH-CH, resulting in the formation of CHCHBr-CH. This reaction follows the characteristics of electrophilic addition, making option 'C' the correct answer.
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The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer?
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The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer?.
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