JEE Exam > JEE Questions > The reaction, CH = CH-CH + HBr → CHCHBr ...
Start Learning for Free
The reaction, CH₂ = CH-CH₃ + HBr → CH₃CHBr - CH₃ is
- a)Nucleophilic addition
- b)Electrophilic substitution
- c)Electrophilic addition
- d)Free radical addition
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic add...
Answer :
Addition of H−x(x→ Halogens ) on alkenes follows electrophilic addition mechanism.
Most Upvoted Answer
The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic add...
Electrophilic Addition
This reaction involves the addition of an electrophile (HBr) to a double bond (CH=CH-CH). The double bond acts as a nucleophile, attacking the electrophile to form a new bond. This type of reaction is known as electrophilic addition.
Mechanism:
1. The double bond in CH=CH-CH acts as a nucleophile and attacks the electrophile HBr.
2. The pi bond breaks as the nucleophile attacks, forming a carbocation intermediate.
3. The Br- ion then attacks the carbocation, forming the final product CHCHBr-CH.
Characteristics of Electrophilic Addition:
- Involves the addition of an electrophile to a double bond.
- Forms a carbocation intermediate.
- Typically occurs with alkenes or alkynes.
- Product is formed by addition of electrophile to the double bond.
In this reaction, the electrophile HBr adds to the double bond in CH=CH-CH, resulting in the formation of CHCHBr-CH. This reaction follows the characteristics of electrophilic addition, making option 'C' the correct answer.
This reaction involves the addition of an electrophile (HBr) to a double bond (CH=CH-CH). The double bond acts as a nucleophile, attacking the electrophile to form a new bond. This type of reaction is known as electrophilic addition.
Mechanism:
1. The double bond in CH=CH-CH acts as a nucleophile and attacks the electrophile HBr.
2. The pi bond breaks as the nucleophile attacks, forming a carbocation intermediate.
3. The Br- ion then attacks the carbocation, forming the final product CHCHBr-CH.
Characteristics of Electrophilic Addition:
- Involves the addition of an electrophile to a double bond.
- Forms a carbocation intermediate.
- Typically occurs with alkenes or alkynes.
- Product is formed by addition of electrophile to the double bond.
In this reaction, the electrophile HBr adds to the double bond in CH=CH-CH, resulting in the formation of CHCHBr-CH. This reaction follows the characteristics of electrophilic addition, making option 'C' the correct answer.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Top Courses for JEEView all
The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer?
Question Description
The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer?.
The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer?.
Solutions for The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The reaction, CH = CH-CH + HBr → CHCHBr - CH isa)Nucleophilic additionb)Electrophilic substitutionc)Electrophilic additiond)Free radical additionCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup