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Two identical conducting plates of plate area A are separated by a distance d to form a parallel plate air capacitor. Now a metal sheet of thickness d/2 is inserted between the plates of the capacitor. The ratio of capacitance before the insertion of plate and after the insertion of plate is
- a)1:2
- b)1:1
- c)2:1
- d)√2:1
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Two identical conducting plates of plate area A are separated by a dis...
Now capacitance of capacitor before inserting metal plate is
C = (ε0A)/d
And after the insertion of any dielectric plate filling the capacitor partially is
C = (ε0A)/[(d-t)+t/K]
We know that K for a metal is infinite thus
C = (ε0A)/(d-t) Here t=d/2
thus C’=(2ε0A)/d=2C
C:C’=1:2
Hence (a) is the correct choice
C = (ε0A)/d
And after the insertion of any dielectric plate filling the capacitor partially is
C = (ε0A)/[(d-t)+t/K]
We know that K for a metal is infinite thus
C = (ε0A)/(d-t) Here t=d/2
thus C’=(2ε0A)/d=2C
C:C’=1:2
Hence (a) is the correct choice
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Two identical conducting plates of plate area A are separated by a dis...
2:3
The capacitance of a parallel plate capacitor is given by:
C = ε0A/d
where ε0 is the permittivity of free space, A is the area of the plates, and d is the distance between them.
Before the insertion of the metal sheet, the capacitance of the capacitor is:
C1 = ε0A/d
After the insertion of the metal sheet, the distance between the plates is reduced to d/2, so the capacitance of the capacitor becomes:
C2 = ε0A/(d/2 + d/2) = ε0A/d
The ratio of capacitance after the insertion of the metal sheet to before the insertion of the metal sheet is:
C2/C1 = (ε0A/d)/(ε0A/d) = 1:1
Therefore, the answer is (b) 1:1.
The capacitance of a parallel plate capacitor is given by:
C = ε0A/d
where ε0 is the permittivity of free space, A is the area of the plates, and d is the distance between them.
Before the insertion of the metal sheet, the capacitance of the capacitor is:
C1 = ε0A/d
After the insertion of the metal sheet, the distance between the plates is reduced to d/2, so the capacitance of the capacitor becomes:
C2 = ε0A/(d/2 + d/2) = ε0A/d
The ratio of capacitance after the insertion of the metal sheet to before the insertion of the metal sheet is:
C2/C1 = (ε0A/d)/(ε0A/d) = 1:1
Therefore, the answer is (b) 1:1.
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Two identical conducting plates of plate area A are separated by a distance d to form a parallel plate air capacitor. Now a metal sheet of thickness d/2 is inserted between the plates of the capacitor. The ratio of capacitance before the insertion of plate and after the insertion of plate isa)1:2b)1:1c)2:1d)√2:1Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two identical conducting plates of plate area A are separated by a distance d to form a parallel plate air capacitor. Now a metal sheet of thickness d/2 is inserted between the plates of the capacitor. The ratio of capacitance before the insertion of plate and after the insertion of plate isa)1:2b)1:1c)2:1d)√2:1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical conducting plates of plate area A are separated by a distance d to form a parallel plate air capacitor. Now a metal sheet of thickness d/2 is inserted between the plates of the capacitor. The ratio of capacitance before the insertion of plate and after the insertion of plate isa)1:2b)1:1c)2:1d)√2:1Correct answer is option 'A'. Can you explain this answer?.
Two identical conducting plates of plate area A are separated by a distance d to form a parallel plate air capacitor. Now a metal sheet of thickness d/2 is inserted between the plates of the capacitor. The ratio of capacitance before the insertion of plate and after the insertion of plate isa)1:2b)1:1c)2:1d)√2:1Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two identical conducting plates of plate area A are separated by a distance d to form a parallel plate air capacitor. Now a metal sheet of thickness d/2 is inserted between the plates of the capacitor. The ratio of capacitance before the insertion of plate and after the insertion of plate isa)1:2b)1:1c)2:1d)√2:1Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two identical conducting plates of plate area A are separated by a distance d to form a parallel plate air capacitor. Now a metal sheet of thickness d/2 is inserted between the plates of the capacitor. The ratio of capacitance before the insertion of plate and after the insertion of plate isa)1:2b)1:1c)2:1d)√2:1Correct answer is option 'A'. Can you explain this answer?.
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Two identical conducting plates of plate area A are separated by a distance d to form a parallel plate air capacitor. Now a metal sheet of thickness d/2 is inserted between the plates of the capacitor. The ratio of capacitance before the insertion of plate and after the insertion of plate isa)1:2b)1:1c)2:1d)√2:1Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Two identical conducting plates of plate area A are separated by a distance d to form a parallel plate air capacitor. Now a metal sheet of thickness d/2 is inserted between the plates of the capacitor. The ratio of capacitance before the insertion of plate and after the insertion of plate isa)1:2b)1:1c)2:1d)√2:1Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Two identical conducting plates of plate area A are separated by a distance d to form a parallel plate air capacitor. Now a metal sheet of thickness d/2 is inserted between the plates of the capacitor. The ratio of capacitance before the insertion of plate and after the insertion of plate isa)1:2b)1:1c)2:1d)√2:1Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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