Find the initial velocity of a car which is stopped in 10 seconds by a...
To find: Initial velocityGiven: Final velocity=0Time=10 secAcceleration= -2.5 m/s^2 (Negative sign as it is retardation)Using:a=v-u/t-2.5=0-u/10-2.5=-u/10-2.5*10=-u-25=-u25=u Therefore, Initial velocity is 25 m/s.
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Find the initial velocity of a car which is stopped in 10 seconds by a...
Given data:
- Time taken to stop the car, t = 10 seconds
- Retardation due to brakes, a = 2.5 m/s^2
Explanation:
The initial velocity of the car can be calculated using the equation of motion:
v = u + at
Where:
- v is the final velocity (which is 0 since the car comes to a stop)
- u is the initial velocity (what we need to find)
- a is the retardation due to brakes
- t is the time taken to stop the car
Step 1: Rearrange the equation to solve for u:
0 = u + a * t
Step 2: Substitute the given values into the equation:
0 = u + 2.5 * 10
Simplifying the equation:
0 = u + 25
To isolate u, we subtract 25 from both sides of the equation:
-25 = u
Therefore, the initial velocity of the car is -25 m/s.
Explanation:
The negative sign indicates that the car was moving in the opposite direction of the applied brakes. It suggests that the car was initially moving in the negative direction and it took 10 seconds for the brakes to reduce its velocity to zero.
It is important to note that the equation used assumes constant retardation throughout the braking process. In real-life scenarios, the retardation may vary due to several factors, such as road conditions and the efficiency of the braking system.
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