A car of mass 2400kg moving with a velocity of 20 m/s is stopped in 10...
Mass= 2400kg, (u)= 20m/s,final velocity (v) = 0 time taken = 10s. find retardation????v= u+at0=20 ×a× 10-20/10 = a-2= a thus retardation= 2m/sii) f= ma f= 2400× (-2) = -4800N cheer
A car of mass 2400kg moving with a velocity of 20 m/s is stopped in 10...
Given:
Mass of car, m = 2400 kg
Initial velocity, u = 20 m/s
Time taken to stop, t = 10 s
Retardation:
Retardation is the rate of decrease of velocity of a moving object. It is given by the formula:
a = (u - v) / t
where,
u = initial velocity
v = final velocity (0 in this case)
t = time taken to stop
Substituting the given values, we get:
a = (20 - 0) / 10
a = 2 m/s²
Therefore, the retardation of the car is 2 m/s².
Retarding force:
Retarding force is the force that acts opposite to the direction of motion of a moving object and causes it to slow down or stop. It is given by the formula:
F = ma
where,
m = mass of the car
a = retardation
Substituting the given values, we get:
F = 2400 × 2
F = 4800 N
Therefore, the retarding force acting on the car is 4800 N.
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