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The population of a town increases every year by 2% of the population at.the beginning of that year.the number of years by which the total increase of population be 40% is?
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Problem: The population of a town increases every year by 2% of the population at the beginning of that year. The number of years by which the total increase of population be 40% is?

Solution:

Let the population at the beginning of a particular year be "P".

The population at the end of the year after a 2% increase will be:

P + (2/100)P = P(1 + 0.02) = 1.02P

Similarly, the population at the end of the second year will be:

1.02P + (2/100)(1.02P) = 1.02P(1 + 0.02) = 1.0404P

The population at the end of the third year will be:

1.0404P + (2/100)(1.0404P) = 1.0404P(1 + 0.02) = 1.061208P

We can see that the population is increasing by a factor of 1.02 each year.

Let "n" be the number of years required for the population to increase by 40%.

Using the formula for compound interest:

P(1 + r)^n = P(1 + 0.02)^n = 1.4P

(1.02)^n = 1.4

n = log(1.4) / log(1.02)

n ≈ 35.6

Therefore, it will take approximately 36 years for the population to increase by 40%.

Conclusion: The number of years by which the total increase of population be 40% is approximately 36 years.
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The population of a town increases every year by 2% of the population at.the beginning of that year.the number of years by which the total increase of population be 40% is?
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