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A boy throws a ball of mass 4 kg vertically downwards for a height of 20 metres. What is the velocity of the ball which touches the ground? (Take g= 10 m/s2)
  • a)
    20 m/s
  • b)
    25 m/s
  • c)
    30 m/s
  • d)
    18 m/s
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A boy throws a ball of mass 4 kg vertically downwards for a height of...
According to the question,
Mass of ball = m = 4 kg, elevation from ground = h = 20 m; v = velocity at touch point
So, mgh = ½ (mv2)
Gives v = 20 m/s
mg = 1/2 (mv2)
2gh = v2
v2 = 2 x 10 x 20 = 400
v = 20 m/sec
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Most Upvoted Answer
A boy throws a ball of mass 4 kg vertically downwards for a height of...
Given data:
- Mass of the ball (m) = 4 kg
- Height (h) = 20 m
- Acceleration due to gravity (g) = 10 m/s^2

Calculating the final velocity:
- The final velocity of the ball when it touches the ground can be calculated using the equation of motion:
v^2 = u^2 + 2gh
where:
v = final velocity
u = initial velocity (0 m/s as it is thrown vertically downwards)
g = acceleration due to gravity (10 m/s^2)
h = height (20 m)
Plugging in the values:
v^2 = 0 + 2 * 10 * 20
v^2 = 400
v = √400
v = 20 m/s
Therefore, the velocity of the ball when it touches the ground is 20 m/s. Hence, the correct answer is option 'A' - 20 m/s.
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A boy throws a ball of mass 4 kg vertically downwards for a height of 20 metres. What is the velocity of the ball which touches the ground? (Take g= 10 m/s2)a)20 m/sb)25 m/sc)30 m/sd)18 m/sCorrect answer is option 'A'. Can you explain this answer?
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