Railways Exam > Railways Questions > Excess-3 code for decimal number 7 is:a)1110...
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Excess-3 code for decimal number 7 is:
- a)1110
- b)1010
- c)1011
- d)1100
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Excess-3 code for decimal number 7 is:a)1110b)1010c)1011d)1100Correct...
For getting excess 3 code, add +3 to the number
7 + 3 = 10
10 In binary is (1010)2
Hence excess 3 code for 7 is (1010)2
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Excess-3 code for decimal number 7 is:a)1110b)1010c)1011d)1100Correct...
Excess-3 Code for Decimal Number 7
Excess-3 code is a non-weighted code used to represent decimal numbers. In this code, each decimal digit is represented by adding 3 to the corresponding binary representation.
Decimal Number 7
To find the excess-3 code for decimal number 7, we first need to convert 7 into binary form. The binary representation of decimal number 7 is 0111.
Excess-3 Code
To get the excess-3 code for decimal number 7, we add 3 to each bit of the binary representation of 7.
- For the first bit (0), adding 3 gives 3 which is represented as 0011 in binary.
- For the second bit (1), adding 3 gives 4 which is represented as 0100 in binary.
- For the third bit (1), adding 3 gives 4 which is represented as 0100 in binary.
- For the fourth bit (1), adding 3 gives 4 which is represented as 0100 in binary.
Therefore, the excess-3 code for decimal number 7 is 0011 0100 0100 0100, which can be simplified to 1010 in binary.
Therefore, the correct option is 'B' - 1010.
Excess-3 code is a non-weighted code used to represent decimal numbers. In this code, each decimal digit is represented by adding 3 to the corresponding binary representation.
Decimal Number 7
To find the excess-3 code for decimal number 7, we first need to convert 7 into binary form. The binary representation of decimal number 7 is 0111.
Excess-3 Code
To get the excess-3 code for decimal number 7, we add 3 to each bit of the binary representation of 7.
- For the first bit (0), adding 3 gives 3 which is represented as 0011 in binary.
- For the second bit (1), adding 3 gives 4 which is represented as 0100 in binary.
- For the third bit (1), adding 3 gives 4 which is represented as 0100 in binary.
- For the fourth bit (1), adding 3 gives 4 which is represented as 0100 in binary.
Therefore, the excess-3 code for decimal number 7 is 0011 0100 0100 0100, which can be simplified to 1010 in binary.
Therefore, the correct option is 'B' - 1010.
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Excess-3 code for decimal number 7 is:a)1110b)1010c)1011d)1100Correct answer is option 'B'. Can you explain this answer? for Railways 2025 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about Excess-3 code for decimal number 7 is:a)1110b)1010c)1011d)1100Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Railways 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Excess-3 code for decimal number 7 is:a)1110b)1010c)1011d)1100Correct answer is option 'B'. Can you explain this answer?.
Excess-3 code for decimal number 7 is:a)1110b)1010c)1011d)1100Correct answer is option 'B'. Can you explain this answer? for Railways 2025 is part of Railways preparation. The Question and answers have been prepared according to the Railways exam syllabus. Information about Excess-3 code for decimal number 7 is:a)1110b)1010c)1011d)1100Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Railways 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Excess-3 code for decimal number 7 is:a)1110b)1010c)1011d)1100Correct answer is option 'B'. Can you explain this answer?.
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