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Let N, x and y be positive integers such that N = x + y, 2 < x < 10 and 14 < y < 23. If N > 25, then how many distinct values are possible for N?
    Correct answer is '6'. Can you explain this answer?
    Verified Answer
    Let N, x and y be positive integers such that N = x + y, 2 < x <...
    Given, 2 < x < 10 and 14 < y < 23 Þ 17 < ( x + y ) < 32 i.e. 17 < N < 32
    But N > 25
    hence 25 < N < 32
    N can take 6 distinct values.
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    Most Upvoted Answer
    Let N, x and y be positive integers such that N = x + y, 2 < x <...
    Since N = x * y and 2^N = (2^x)^y, we can rewrite the equation as:

    2^(x * y) = (2^x)^y

    Taking the logarithm of both sides with base 2, we get:

    x * y = x * y

    This equation is always true for any positive integer values of x and y. Therefore, there are infinitely many positive integer solutions for N, x, and y that satisfy the equation.
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    Let N, x and y be positive integers such that N = x + y, 2 < x < 10 and 14 < y < 23. If N > 25, then how many distinct values are possible for N?Correct answer is '6'. Can you explain this answer?
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