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Light is incident from a medium of refractive index n = 1.5 onto dry air. What will be the smallest angle of
incidence in degrees (two decimal places) for which the light is not transmitted into air ?
incidence in degrees (two decimal places) for which the light is not transmitted into air ?
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Light is incident from a medium of refractive index n = 1.5 onto dry a...
**Solution:**
To find the smallest angle of incidence for which the light is not transmitted into air, we can use the concept of total internal reflection.
**Total Internal Reflection:**
Total internal reflection occurs when light travels from a medium with a higher refractive index to a medium with a lower refractive index and the angle of incidence is greater than the critical angle. In this case, all the light is reflected back into the medium with the higher refractive index.
**Critical Angle:**
The critical angle is the angle of incidence that results in an angle of refraction of 90 degrees. It can be calculated using the formula:
sin(critical angle) = 1/n
where n is the refractive index of the medium.
**Given:**
Refractive index of the medium = 1.5 (from medium to air)
**Calculating the Critical Angle:**
Using the formula for the critical angle, we can substitute the refractive index value:
sin(critical angle) = 1/1.5
Solving for the critical angle:
critical angle = arcsin(1/1.5)
Using a scientific calculator, we can find the value of the critical angle:
critical angle ≈ 41.81 degrees (rounded to two decimal places)
Therefore, the smallest angle of incidence for which the light is not transmitted into air is approximately 41.81 degrees. This means that any angle of incidence greater than 41.81 degrees will result in total internal reflection, where the light is reflected back into the medium with the higher refractive index (in this case, the medium with refractive index 1.5).
To find the smallest angle of incidence for which the light is not transmitted into air, we can use the concept of total internal reflection.
**Total Internal Reflection:**
Total internal reflection occurs when light travels from a medium with a higher refractive index to a medium with a lower refractive index and the angle of incidence is greater than the critical angle. In this case, all the light is reflected back into the medium with the higher refractive index.
**Critical Angle:**
The critical angle is the angle of incidence that results in an angle of refraction of 90 degrees. It can be calculated using the formula:
sin(critical angle) = 1/n
where n is the refractive index of the medium.
**Given:**
Refractive index of the medium = 1.5 (from medium to air)
**Calculating the Critical Angle:**
Using the formula for the critical angle, we can substitute the refractive index value:
sin(critical angle) = 1/1.5
Solving for the critical angle:
critical angle = arcsin(1/1.5)
Using a scientific calculator, we can find the value of the critical angle:
critical angle ≈ 41.81 degrees (rounded to two decimal places)
Therefore, the smallest angle of incidence for which the light is not transmitted into air is approximately 41.81 degrees. This means that any angle of incidence greater than 41.81 degrees will result in total internal reflection, where the light is reflected back into the medium with the higher refractive index (in this case, the medium with refractive index 1.5).
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Light is incident from a medium of refractive index n = 1.5 onto dry air. What will be the smallest angle ofincidence in degrees (two decimal places) for which the light is not transmitted into air ? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Light is incident from a medium of refractive index n = 1.5 onto dry air. What will be the smallest angle ofincidence in degrees (two decimal places) for which the light is not transmitted into air ? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Light is incident from a medium of refractive index n = 1.5 onto dry air. What will be the smallest angle ofincidence in degrees (two decimal places) for which the light is not transmitted into air ?.
Light is incident from a medium of refractive index n = 1.5 onto dry air. What will be the smallest angle ofincidence in degrees (two decimal places) for which the light is not transmitted into air ? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Light is incident from a medium of refractive index n = 1.5 onto dry air. What will be the smallest angle ofincidence in degrees (two decimal places) for which the light is not transmitted into air ? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Light is incident from a medium of refractive index n = 1.5 onto dry air. What will be the smallest angle ofincidence in degrees (two decimal places) for which the light is not transmitted into air ?.
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