The reaction of ethanol with H2SO4 does not give a specific product. This is because the reaction between ethanol and H2SO4 is an acid-catalyzed dehydration reaction, which involves the removal of water from the ethanol molecule. The reaction proceeds through an intermediate called an oxonium ion, which is formed when the hydrogen atom of the -OH group in ethanol is protonated by the H2SO4. This results in the formation of an ethyl oxonium ion.

Dehydration Reaction:
1. Protonation of ethanol: H2SO4 + CH3CH2OH → CH3CH2OH2+ + HSO4-
2. Formation of ethyl oxonium ion: CH3CH2OH2+ → CH3CH2O+ + H3O+
3. Removal of water: CH3CH2O+ + HSO4- → CH2=CH2 + H3O+ + HSO4-

Lack of Specific Product:
The lack of a specific product in this reaction is due to the fact that the ethyl oxonium ion can undergo different reactions depending on the conditions and other reactants present. It can either undergo further dehydration to form ethylene or react with the HSO4- ion to form ethyl hydrogensulfate. The reaction conditions, such as temperature and concentration, can influence the formation of these different products.

Formation of Ethylene:
If the reaction conditions favor further dehydration, the ethyl oxonium ion can lose a proton from the H3O+ ion, resulting in the formation of ethylene (CH2=CH2). The overall reaction can be represented as:

CH3CH2O+ + H3O+ → CH2=CH2 + H3O2+

Formation of Ethyl Hydrogensulfate:
Alternatively, if the reaction conditions favor the reaction between the ethyl oxonium ion and the HSO4- ion, ethyl hydrogensulfate (CH3CH2OSO3H) can be formed. The overall reaction can be represented as:

CH3CH2O+ + HSO4- → CH3CH2OSO3H

Summary:
In summary, the reaction of ethanol with H2SO4 does not give a specific product because it is an acid-catalyzed dehydration reaction. The formation of different products, such as ethylene or ethyl hydrogensulfate, depends on the reaction conditions and the presence of other reactants.