The point (a, -a) does not lie on the graph ofa)y = xb)x + y = 0c)x = ...
Explanation:
To determine whether the point (a, -a) lies on the graph of a given equation, we substitute the values of x and y from the point into the equation and check if the equation holds true.
a) y = x:
When we substitute x = a and y = -a into the equation y = x, we get:
- a = a
This equation is true, which means the point (a, -a) lies on the graph of y = x.
b) xy = 0:
When we substitute x = a and y = -a into the equation xy = 0, we get:
- a * (-a) = 0
a^2 = 0
This equation is not true unless a = 0. Therefore, the point (a, -a) does not lie on the graph of xy = 0.
c) x = a:
When we substitute x = a and y = -a into the equation x = a, we get:
a = a
This equation is true, which means the point (a, -a) lies on the graph of x = a.
d) y = -a:
When we substitute x = a and y = -a into the equation y = -a, we get:
- a = -a
This equation is true, which means the point (a, -a) lies on the graph of y = -a.
Conclusion:
From the analysis above, we can see that the point (a, -a) does not lie on the graph of xy = 0, so the correct answer is option A.
The point (a, -a) does not lie on the graph ofa)y = xb)x + y = 0c)x = ...
Clearly a ≠ -a.
Hence, (a, -a) doesn't lie on y = x.