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A ship travels due east at 10 km/hr.Another ship heading 30 east of north is always due north from the first ship.The speed of second ship in km/hr is
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A ship travels due east at 10 km/hr.Another ship heading 30 east of no...
Analysis:
To find the speed of the second ship, we need to break down the motion of both ships into their respective components. Let's consider the first ship's motion first.
First Ship:
- Speed: 10 km/hr
- Direction: Due east
Second Ship:
- Speed: Unknown (Let's call it v km/hr)
- Direction: 30° east of north
To find the speed of the second ship, we can use vector addition. Let's break down the second ship's motion into its northward and eastward components.
Second Ship's Components:
- Northward Component: v * cos(30°)
- Eastward Component: v * sin(30°)
Since the second ship is always due north from the first ship, its northward component should be equal to the first ship's eastward component.
Equation:
v * cos(30°) = 10 km/hr
Now, we can solve this equation to find the value of v.
Solving the Equation:
v * cos(30°) = 10 km/hr
v = 10 km/hr / cos(30°)
v = 10 km/hr / (√3/2)
v = (10 * 2) / √3
v = 20 / √3
v ≈ 11.55 km/hr
So, the speed of the second ship is approximately 11.55 km/hr.
To find the speed of the second ship, we need to break down the motion of both ships into their respective components. Let's consider the first ship's motion first.
First Ship:
- Speed: 10 km/hr
- Direction: Due east
Second Ship:
- Speed: Unknown (Let's call it v km/hr)
- Direction: 30° east of north
To find the speed of the second ship, we can use vector addition. Let's break down the second ship's motion into its northward and eastward components.
Second Ship's Components:
- Northward Component: v * cos(30°)
- Eastward Component: v * sin(30°)
Since the second ship is always due north from the first ship, its northward component should be equal to the first ship's eastward component.
Equation:
v * cos(30°) = 10 km/hr
Now, we can solve this equation to find the value of v.
Solving the Equation:
v * cos(30°) = 10 km/hr
v = 10 km/hr / cos(30°)
v = 10 km/hr / (√3/2)
v = (10 * 2) / √3
v = 20 / √3
v ≈ 11.55 km/hr
So, the speed of the second ship is approximately 11.55 km/hr.
Community Answer
A ship travels due east at 10 km/hr.Another ship heading 30 east of no...
20 kmph
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A ship travels due east at 10 km/hr.Another ship heading 30 east of north is always due north from the first ship.The speed of second ship in km/hr is
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A ship travels due east at 10 km/hr.Another ship heading 30 east of north is always due north from the first ship.The speed of second ship in km/hr is for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A ship travels due east at 10 km/hr.Another ship heading 30 east of north is always due north from the first ship.The speed of second ship in km/hr is covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ship travels due east at 10 km/hr.Another ship heading 30 east of north is always due north from the first ship.The speed of second ship in km/hr is.
A ship travels due east at 10 km/hr.Another ship heading 30 east of north is always due north from the first ship.The speed of second ship in km/hr is for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A ship travels due east at 10 km/hr.Another ship heading 30 east of north is always due north from the first ship.The speed of second ship in km/hr is covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A ship travels due east at 10 km/hr.Another ship heading 30 east of north is always due north from the first ship.The speed of second ship in km/hr is.
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