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The Td point group has 24 elements and 5 classes. Given that it has two 3-d irreducible representation, the number of one dimensional it reduicible representation is?
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The Td point group has 24 elements and 5 classes. Given that it has tw...
Introduction:
The Td point group is a symmetry group that describes the symmetry elements of a regular tetrahedron. It has 24 elements and 5 classes. In this group, there are two 3-dimensional irreducible representations. We are asked to determine the number of one-dimensional irreducible representations.

Solution:
To find the number of one-dimensional irreducible representations (irreps), we can use the formula:

Number of one-dimensional irreps = Total number of irreps - Number of three-dimensional irreps

Step 1: Find the total number of irreps
The total number of irreps can be determined by counting the number of classes in the group. In the case of the Td point group, there are 5 classes.

Step 2: Find the number of three-dimensional irreps
We are given that there are two 3-dimensional irreps in the Td point group.

Step 3: Calculate the number of one-dimensional irreps
Using the formula mentioned earlier, we can calculate the number of one-dimensional irreps:

Number of one-dimensional irreps = Total number of irreps - Number of three-dimensional irreps
= 5 - 2
= 3

Therefore, the Td point group has 3 one-dimensional irreducible representations.

Summary:
The Td point group has 24 elements and 5 classes. It has two 3-dimensional irreducible representations. Using the formula, we find that it also has 3 one-dimensional irreps.
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The Td point group has 24 elements and 5 classes. Given that it has two 3-d irreducible representation, the number of one dimensional it reduicible representation is?
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