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An electric dipole of moment p is placed parallel to the uniform electric field. The amount of work done in rotating the dipole by 90° is
- a)2pE
- b)pE
- c)pE/2
- d)Zero
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
An electric dipole of moment p is placed parallel to the uniform elect...
W = pE (cos θ1 – cos θ2)
θ1 = 0°
θ2 = 90°
W = pE (cos 0° – cos 90°)
= pE (1 – 0)
= PE
θ1 = 0°
θ2 = 90°
W = pE (cos 0° – cos 90°)
= pE (1 – 0)
= PE
Most Upvoted Answer
An electric dipole of moment p is placed parallel to the uniform elect...
Degrees from its initial position to a position perpendicular to the field is given by:
W = -pEcos(90°)
Since the dipole is parallel to the field initially, the angle between the dipole moment and the electric field is 0°. When the dipole is rotated by 90°, the angle between the dipole moment and the electric field becomes 90°.
Using the formula for work done by a torque (τ) in rotating an object by an angle (θ):
W = τθ
We can express the torque as:
τ = pEsinθ
where θ is the angle between the dipole moment and the electric field. When θ = 90°, sinθ = 1, so the torque is maximum:
τ = pE
Substituting this into the work equation, we get:
W = τθ = pEcos(90°) = -pE
Therefore, the amount of work done in rotating the dipole by 90 degrees from its initial position to a position perpendicular to the field is -pE. This work is negative, indicating that the electric field does negative work on the dipole, which means that the dipole loses potential energy.
W = -pEcos(90°)
Since the dipole is parallel to the field initially, the angle between the dipole moment and the electric field is 0°. When the dipole is rotated by 90°, the angle between the dipole moment and the electric field becomes 90°.
Using the formula for work done by a torque (τ) in rotating an object by an angle (θ):
W = τθ
We can express the torque as:
τ = pEsinθ
where θ is the angle between the dipole moment and the electric field. When θ = 90°, sinθ = 1, so the torque is maximum:
τ = pE
Substituting this into the work equation, we get:
W = τθ = pEcos(90°) = -pE
Therefore, the amount of work done in rotating the dipole by 90 degrees from its initial position to a position perpendicular to the field is -pE. This work is negative, indicating that the electric field does negative work on the dipole, which means that the dipole loses potential energy.
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An electric dipole of moment p is placed parallel to the uniform electric field. The amount of work done in rotating the dipole by 90° isa)2pEb)pEc)pE/2d)ZeroCorrect answer is option 'B'. Can you explain this answer?
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