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A constant voltage is applied between the two ends of a uniform metallic wire, heat ‘H’ is developed in it. If another wire of the same material, double the radius and twice the length as compared to original wire is used, then the heat developed in it will be:
- a)H/2
- b)H
- c)2H
- d)4H
Correct answer is option 'C'. Can you explain this answer?
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A constant voltage is applied between the two ends of a uniform metall...
∵ V = constant
=
H′ /H = 2/1
H′ = 2H
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A constant voltage is applied between the two ends of a uniform metall...
Is generated in the wire due to the flow of electric current. This heat is a result of the resistance of the wire.
When a constant voltage is applied to a metallic wire, it creates an electric field within the wire. This electric field exerts a force on the free electrons present in the wire, causing them to move. The movement of these electrons constitutes an electric current.
As the electrons move through the wire, they collide with the atoms and other electrons present in the wire. These collisions result in the transfer of kinetic energy from the moving electrons to the atoms, causing them to vibrate more vigorously. This increased vibrational motion of the atoms is interpreted as an increase in temperature, which leads to the generation of heat.
The amount of heat generated in the wire is proportional to the square of the current passing through it (I^2) and the resistance of the wire (R). This relationship is given by Joule's Law of Heating, which states that the heat produced (H) is equal to the product of the current squared, the resistance, and the time for which the current flows:
H = I^2 * R * t
Where H is the heat generated, I is the current, R is the resistance, and t is the time.
In summary, when a constant voltage is applied to a metallic wire, heat is generated due to the resistance of the wire. This heat is a result of the collisions between the moving electrons and the atoms, leading to an increase in temperature.
When a constant voltage is applied to a metallic wire, it creates an electric field within the wire. This electric field exerts a force on the free electrons present in the wire, causing them to move. The movement of these electrons constitutes an electric current.
As the electrons move through the wire, they collide with the atoms and other electrons present in the wire. These collisions result in the transfer of kinetic energy from the moving electrons to the atoms, causing them to vibrate more vigorously. This increased vibrational motion of the atoms is interpreted as an increase in temperature, which leads to the generation of heat.
The amount of heat generated in the wire is proportional to the square of the current passing through it (I^2) and the resistance of the wire (R). This relationship is given by Joule's Law of Heating, which states that the heat produced (H) is equal to the product of the current squared, the resistance, and the time for which the current flows:
H = I^2 * R * t
Where H is the heat generated, I is the current, R is the resistance, and t is the time.
In summary, when a constant voltage is applied to a metallic wire, heat is generated due to the resistance of the wire. This heat is a result of the collisions between the moving electrons and the atoms, leading to an increase in temperature.
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A constant voltage is applied between the two ends of a uniform metallic wire, heat ‘H’ is developed in it. If another wire of the same material, double the radius and twice the length as compared to original wire is used, then the heat developed in it will be:a)H/2b)Hc)2Hd)4HCorrect answer is option 'C'. Can you explain this answer?
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