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A 20 volt AC is applied to a circuit consisting of a resistance and a coil with negligible resistance. If the voltage across the resistance is 12 volt, the voltage across the coil is:
- a)16 V
- b)10 V
- c)8 V
- d)6 V
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A 20 volt AC is applied to a circuit consisting of a resistance and a ...
VR = Effective voltage across R
∴ VR = Ieff R
VL = Effective voltage across L
VL = Ieff × L
Net V =
=
20 =
(20)2 = (12)2 + VL2
400 = 144 + VL2
VL = √400 - 144 = √266 = 16 volts
Most Upvoted Answer
A 20 volt AC is applied to a circuit consisting of a resistance and a ...
Given:
- Voltage applied to the circuit (V) = 20 V
- Voltage across the resistance (VR) = 12 V
To find:
- Voltage across the coil (VC)
Solution:
1. Understanding the Circuit:
- The circuit consists of a resistance and a coil with negligible resistance.
- The voltage applied to the circuit is 20 V.
- The voltage across the resistance is 12 V.
2. Applying Kirchhoff's Voltage Law (KVL):
- According to Kirchhoff's Voltage Law, the sum of the voltage drops across all elements in a closed loop is equal to the applied voltage.
- In this case, the applied voltage (20 V) is equal to the sum of the voltage drops across the resistance (VR) and the coil (VC).
3. Applying KVL to the Circuit:
- Applying KVL to the circuit, we have:
- VR + VC = V
4. Substituting Known Values:
- Substituting the known values, we have:
- 12 V + VC = 20 V
5. Solving for VC:
- Rearranging the equation, we get:
- VC = 20 V - 12 V
- VC = 8 V
6. Conclusion:
- The voltage across the coil (VC) is 8 V.
- Voltage applied to the circuit (V) = 20 V
- Voltage across the resistance (VR) = 12 V
To find:
- Voltage across the coil (VC)
Solution:
1. Understanding the Circuit:
- The circuit consists of a resistance and a coil with negligible resistance.
- The voltage applied to the circuit is 20 V.
- The voltage across the resistance is 12 V.
2. Applying Kirchhoff's Voltage Law (KVL):
- According to Kirchhoff's Voltage Law, the sum of the voltage drops across all elements in a closed loop is equal to the applied voltage.
- In this case, the applied voltage (20 V) is equal to the sum of the voltage drops across the resistance (VR) and the coil (VC).
3. Applying KVL to the Circuit:
- Applying KVL to the circuit, we have:
- VR + VC = V
4. Substituting Known Values:
- Substituting the known values, we have:
- 12 V + VC = 20 V
5. Solving for VC:
- Rearranging the equation, we get:
- VC = 20 V - 12 V
- VC = 8 V
6. Conclusion:
- The voltage across the coil (VC) is 8 V.
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A 20 volt AC is applied to a circuit consisting of a resistance and a coil with negligible resistance. If the voltage across the resistance is 12 volt, the voltage across the coil is:a)16 Vb)10 Vc)8 Vd)6 VCorrect answer is option 'A'. Can you explain this answer?
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