Class 12 Exam > Class 12 Questions > When two bulbs A (40 W, 220 V) and B (60 W, 2...
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When two bulbs A (40 W, 220 V) and B (60 W, 220 V) are connected in series, which bulb is brighter.
- a)bulb A
- b)bulb B
- c)both
- d)none of these
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
When two bulbs A (40 W, 220 V) and B (60 W, 220 V) are connected in se...
As
P = V x i = i2R = V2/R
R for 40 W bulb
R40 = V2/P = (200)2/40 = 1210Ω
R for 60 W bulb
R60 = V2/P = (200)2/60 = 806.67Ω
⇒ R40>R60
When two bulbs are connected in series, current flow through them is same and power is calculated using the following formula:
P = i2R or P ∞ R
Since, R40 > R60 therefore, P40 > P60 Therefore, power dissipation is large in 40 W bulb as compare to 60 W bulb. 40 W bulb is brighter than 60 W.
P = V x i = i2R = V2/R
R for 40 W bulb
R40 = V2/P = (200)2/40 = 1210Ω
R for 60 W bulb
R60 = V2/P = (200)2/60 = 806.67Ω
⇒ R40>R60
When two bulbs are connected in series, current flow through them is same and power is calculated using the following formula:
P = i2R or P ∞ R
Since, R40 > R60 therefore, P40 > P60 Therefore, power dissipation is large in 40 W bulb as compare to 60 W bulb. 40 W bulb is brighter than 60 W.
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When two bulbs A (40 W, 220 V) and B (60 W, 220 V) are connected in series, which bulb is brighter.a)bulb Ab)bulb Bc)bothd)none of theseCorrect answer is option 'A'. Can you explain this answer?
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