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The mid-value of a class interval is 42. If the class size is 10, then the upper and lower limits of the class are:
  • a)
    47.5 and 37.5
  • b)
    47 and 37
  • c)
    37.5 and 47.5
  • d)
    37 and 47
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The mid-value of a class interval is 42. If the class size is 10, then...
Let the lower limit of a class = x
class size = 10
Upper limit = x + 10
Now, mid - value =  = x + 5 = 42 (given)
x = 37 = lower limit
x + 10 = 47 = upper limit
pper and lower limits are 47, 37
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Most Upvoted Answer
The mid-value of a class interval is 42. If the class size is 10, then...
Explanation:

To find the upper and lower limits of a class interval, we need to know the mid-value and the class size.

Given:
Mid-value = 42
Class size = 10

Calculating the lower limit:
The lower limit is found by subtracting half of the class size from the mid-value.

Lower limit = Mid-value - (Class size / 2)
Lower limit = 42 - (10 / 2)
Lower limit = 42 - 5
Lower limit = 37

Calculating the upper limit:
The upper limit is found by adding half of the class size to the mid-value.

Upper limit = Mid-value + (Class size / 2)
Upper limit = 42 + (10 / 2)
Upper limit = 42 + 5
Upper limit = 47

Thus, the upper and lower limits of the class interval are 47 and 37 respectively.

Therefore, the correct answer is option B) 47 and 37.
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The mid-value of a class interval is 42. If the class size is 10, then the upper and lower limits of the class are:a)47.5 and 37.5b)47 and 37c)37.5 and 47.5d)37 and 47Correct answer is option 'B'. Can you explain this answer?
Question Description
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