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In a frequency distribution, the class-width is 4 and the lower limit of first class is 10. If there are six classes, the upper limit of last class is
- a)32
- b)34
- c)26
- d)30
Correct answer is option 'B'. Can you explain this answer?
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In a frequency distribution, the class-width is 4 and the lower limit ...
10+(6�4)=34 is the last class upper limit
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In a frequency distribution, the class-width is 4 and the lower limit ...
Given information:
- Class width = 4
- Lower limit of first class = 10
- Number of classes = 6
Calculating the upper limit of the last class:
The upper limit of a class can be calculated using the formula:
Upper limit = Lower limit + Class width
Since the class width is given as 4 and the lower limit of the first class is given as 10, we can calculate the upper limit of the first class as:
Upper limit of first class = 10 + 4 = 14
Calculating the upper limits of the subsequent classes:
To find the upper limit of the second class, we add the class width to the upper limit of the first class:
Upper limit of second class = 14 + 4 = 18
Similarly, we can find the upper limits of the third, fourth, fifth, and sixth classes by adding the class width to the upper limit of the previous class:
Upper limit of third class = 18 + 4 = 22
Upper limit of fourth class = 22 + 4 = 26
Upper limit of fifth class = 26 + 4 = 30
Upper limit of sixth class = 30 + 4 = 34
Conclusion:
Since there are six classes and the upper limit of the last class is 34, the correct answer is option 'B' (34).
- Class width = 4
- Lower limit of first class = 10
- Number of classes = 6
Calculating the upper limit of the last class:
The upper limit of a class can be calculated using the formula:
Upper limit = Lower limit + Class width
Since the class width is given as 4 and the lower limit of the first class is given as 10, we can calculate the upper limit of the first class as:
Upper limit of first class = 10 + 4 = 14
Calculating the upper limits of the subsequent classes:
To find the upper limit of the second class, we add the class width to the upper limit of the first class:
Upper limit of second class = 14 + 4 = 18
Similarly, we can find the upper limits of the third, fourth, fifth, and sixth classes by adding the class width to the upper limit of the previous class:
Upper limit of third class = 18 + 4 = 22
Upper limit of fourth class = 22 + 4 = 26
Upper limit of fifth class = 26 + 4 = 30
Upper limit of sixth class = 30 + 4 = 34
Conclusion:
Since there are six classes and the upper limit of the last class is 34, the correct answer is option 'B' (34).
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Community Answer
In a frequency distribution, the class-width is 4 and the lower limit ...
I think the answer should be 34
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In a frequency distribution, the class-width is 4 and the lower limit of first class is 10. If there are six classes, the upper limit of last class isa)32b)34c)26d)30Correct answer is option 'B'. Can you explain this answer?
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